Question

Question 13 CNNBC recently reported that the mean annual cost of auto insurance is 991 dollars. Assume the standard deviation is 144 dollars. You will use a simple random sample of 78 auto insurance policies. Find the probability that a single randomly selected policy has a mean value between 1010.6 and 1038.3 dollars. P(1010.6 < X < 1038.3) = 78 has a mean value between 1010.6 and Find the probability that a random sample of size n = 1038.3 dollars. P(1010.6 <M < 1038.3) - Enter your answers as numbers accurate to 4 decimal places. Question Help: Message instructor Calculator Submit Question

Answer 1

Solutions Given U=991, 9=144 42 nal P(1010.6 < x < 1038.3) CLT I can By write it as 1010. 6-aal 1038-3-991 Р ( Z < 144 1५५ P(0.136 < z < 0.328) P (220.328) - P(Z < 0.136) 0. 62854 0.55409 0.07uus 0.0745 Ars n= 78 Jo 1038-3-999 P ( 10 10.6 < x < 1038.3) 10 10.6-991 144/578 < X-M lin < 144/578 P (1.202 <z < 2.901) P (222.901) - P(221-202) 0.99814 0.88532 = 0.11282 = 0.1128 Ans.