Question

For the traded as shown, determine the member forces in C, E, and in onewtons. Use the fractions. Othereof problem, de mosten KN 7 PIN B 33mm magnitude IN ta magde Fro Bague EN Also, Identity were force members in the trust your newers as a commodo

Answer 1

Soph 8KN 7KN 22KN A D → 7KN 4m H HE -3m the -3m - zm VH We have to calculate force in members "BC, Cf & fui of teellss. for which we will use the method of section to analyse The treuss. Cut the trust such that all three members will be cut down 7KN to → 7KN بادی علیا 7 22KN A 8KN B D N cu HE H st un calculation of Suppdet Reactions from the equation of Teuss. equilibrium for the whole Efx = 0 in Met 22+7 =0 十个16 Не = -29 KN Efy=0 VE + VH-8- 3 =0 Scanned with CS CamScanner VE TVM = 15 - { T ]

EME=0 2284 + 8x3+ 7x6 + 7x4 - Vito = 0 {+2 G VH = 182 g A VH = 20-22 KN so from ear is VE = 15- 20.22 KN VE = -5-226N بيبولى -- a force Calculation : from Left side of the section. 8KN 22KN JB C for FFC 29 kne TV Ffur 5:22 KN Toking moment of the whole too section about t' as zero EM 20 - 5.22X 6+ 29x4 – 8x3-4x fon = 0 Hefur = 60.68 fe = 15:17 KN { Tensile. fur CS Scanned with CamScanner

Now from Right side of the section. 7KN I 7 KN FEB F For Fit Forf H - KE 20.22KN Now Taking moment of whole section about point f as zero EME=0 FRX4 20-22x6 fipx4 =- 50 15 7x3 + 784- 72.32 -18.08 KN compressive. FEB ah Zero Now taking moment about point in as 7KN FEB 7KN for H fort 67 20.22kw Tano = 4 3 0 = 53.130 of 'Por is So Horizontal composient fer Caso so Em = 0 - FCB X4 - Fof caso x 4 +7x4-20.22x3=0 fic C103653:13) x4 2 -(-18.08)x4+28- 20.22x3 CS Scanned with CamScanner

Fcf Cos (53:13)*4 = 39.66 fcf = 16-525 kn Ich {Tensile so 18.08 KN Forces in the required members are FBC (compressive) 16.525 KN (Tensile) Ffur 15..17KN (Tensile) Fer - با Also, There are No zero facce members zero force members a 0 CS Scanned with CamScanner