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This Question: 1 pt 9 of 30 (complete This Test: 30 pts possibile o Theandem variatiews uniform distribution from 11 to 53 Wh
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Answer #1

We are given the distribution here as:

X \sim U(a = 11, b = 53)

Therefore the mean and standard deviation here are computed as:

\mu = \frac{a + b}{2} = \frac{11 + 53}{2}= 32

\sigma = \frac{b - a}{\sqrt{12}} = \frac{53 - 11}{\sqrt{12}} = 12.1244

The probability that the random variable lies within 1.22 standard deviations of the mean is computed here as:

P( 32 - 1.22*12.1244 < X < 32 + 1.22*12.1244)

= P(17.21 < X < 46.79)

= (46.79 - 17.21) / (53 - 11)

= 0.7043

Therefore 70.43% is the required probability here. Therefore E is the correct answer here.

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