Sol)
Given
n = 182
Sample mean ( xbar ) = 32.8
Sample standard deviation ( s ) = 6.2
The confidence is 90%
Population standard deviation is unknown so we use t distribution
Degreesof freedom = df = n - 1 = 182 - 1= 181
Alpha = 1 - 0.90
= 0.1
Alpha / 2 = 0.1 / 2 = 0.05
T value for df = 181 and alpha /2 = 0.05 is
T value( t alpha / 2 ) = 1.653316
Option A
T ( alpha / 2 ) = 1.653316
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