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Assume that we want to construct a confidence interval. Do one of the following, as appropriate: (a) find the critical value

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Answer #1

Sol)

Given

n = 182

Sample mean ( xbar ) = 32.8

Sample standard deviation ( s ) = 6.2

The confidence is 90%

Population standard deviation is unknown so we use t distribution

Degreesof freedom = df = n - 1 = 182 - 1= 181

Alpha = 1 - 0.90

= 0.1

Alpha / 2 = 0.1 / 2 = 0.05

T value for df = 181 and alpha /2 = 0.05 is

T value( t alpha / 2 ) = 1.653316

Option A

T ( alpha / 2 ) = 1.653316

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