The Answer is None of the above can be inserted.
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When there is a functional dependency X->Y
the set of attributes in X should uniquely determine set of attributes in Y.
It means that each combination of values in X should precisely be related with one combination of Y.
Given relation: R(A, B, C, D, E)
F = {AB-->C, CD-->E, E-->B, CE-->A}
Tuple (1, 1, 2, 2, 3) already exists in R
Let us try inserting new tuple
>>>(0, 1, 2, 4, 3)
CE-->A is violated
Because C = 2, E = 3, A = 1 in existing tuple (1, 1, 2, 2, 3)
but C = 2, E = 3, A = 0 in newly inserted tuple (0, 1, 2, 4, 3)
Same combination of C,E is related to two different values of A. Hence, CE-->A is violated
So this tuple cannot be inserted,
>>>(1, 1, 2, 2, 4)
CD-->E is violated
Because C = 2, D = 2, E = 3 in existing tuple (1, 1, 2, 2, 3)
but C = 2, D = 2, E = 4 in newly inserted tuple (1, 1, 2, 2, 4)
Same combination of C,D is related to two different values of E. Hence, CD-->E is violated
So this tuple cannot be inserted,
>>>(1, 2, 2, 2, 3)
E-->B is violated
Because E = 3, B =1 in existing tuple (1, 1, 2, 2, 3)
but E = 3, B = 2 in newly inserted tuple (1, 2, 2, 2, 3)
Same combination of E is related to two different values of B .Hence, E-->B is violated
So this tuple cannot be inserted,
>>>(1, 1, 3, 2, 3)
AB-->C is violated
Because A = 1, B =1, C = 2 in existing tuple (1, 1, 2, 2, 3)
but A = 1, B =1, C = 3 i in newly inserted tuple (1, 1, 3, 2, 3)
Same combination of A, B is related to two different values of C. Hence, AB-->C is violated
So this tuple cannot be inserted,
Hence
The Answer is None of the above can be inserted.
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