Question

Question 6 6.25 pts The figure depicts a square box with charges at each vertex. The side length of the box is 2.5 m. The charges are 91 = 1.5 nC,92 = 3 nC,93 = 4.5 nC, and 94 = 6 nC. What is the electric potential at point P, located halfway between charges 93 and 94 on the bottom side? = 91 92 93 P 94

Answer 1

9 2 1.5x109 C q2 = 3x159c B A S 2.5 M С ry 4= 6x109 C Pk 1.25 1.25 v=9x109 [15x10 Ans 2.5 4.5X109 c 23 qy Here, AP = Jac²tep² = $(2.5) 2 (1.252 AP = 2.795.m. AP = BP = Electonic potential at point p =y. ay kleum 4.5x109 6x109 2-795 1.25 2-795 93 t. + n ar + ry M3 v= M2 3x109 1.25 2.795 x 16 v=9x10²x10-9 90 valt Mence, the Electric Potential at point go volt р De =

v=A&3_ Bre? Now, differentiating w.rot. Sed 1 (Aro - Ber? = 3 Ar? - aBr du der du ہوے ہونے -du E = ㄷ ☺ Tere so 3 Aur? - 2 Br = 3 A² = 2 Br 2 B 3A de a 2x3.33 3 X 6.66 I r - 3 Zero, so for Electric field the distance r = 13