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Problem A Find the amplitude, the period in radians, the phase shift in radians, and the vertical shift. Then sketch the grap
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Answer #1

The general equation of sine or cosine function are

\\ y= a\sin\left ( bx-c \right )+d\\ \\and \\ \\ y= a\ cos\left ( bx-c \right )+d\\ \\ Where, \\ \\Amplitude=a\\ \\Period= \frac{2\pi}{b}\\ \\Phase \ shift= \frac{c}{b}\\ \\ Vertical\ shift= d\\ \\

\\ (1) \\ y= -2+\frac{1}{2}\ cos \left ( 3\theta+\frac{3\pi}{4} \right )\\ \\ Where, \\ \\Amplitude=a=\frac{1}{2}\\ \\Period= \frac{2\pi}{b}=\frac{2\pi}{3}\\ \\Phase \ shift= \frac{c}{b}= -\frac{3\pi}{4}\times\frac{1}{3}= -\frac{\pi}{4} \\ \\ Vertical\ shift= d= -2\\ \\ Graph: \\ \\

у 4 (1) 3.5 3 2.5 2 1.5 1 0.5 -П -Зry/4 -п/2 -4 0 4 п/2 Зry/4 п -0.5 1 -1.5 -2 -2.5 -3 -3.5 -4 -4.5 -5 -5.5 -6 -6.5

\\ (2) \\ y=2\sin\left ( \frac {\theta}{2}+\frac{2\pi}{3} \right )-1\\ \\ Where, \\ \\Amplitude=a=2\\ \\Period= \frac{2\pi}{b}=\frac{2\pi}{\frac{1}{2}}=4\pi\\ \\Phase \ shift= \frac{c}{b}= -\frac{2\pi}{3}\times2= -\frac{4\pi}{3} \\ \\ Vertical\ shift= d= -1\\ \\ Graph: \\ \\

y 22 (2) 21 20 19 18 17 16 15 14 13 12 11 10 -9 -8 7 6 5 -4 -3 2 1- -40 -8TL/3 -4T1/3 0 4T1/3 8TL/3 4T0 -1 -2 -3 -4 -5 -6 -7

\\ (3) \\ y=3\sin\left ( 3\theta+\frac{\pi}{2} \right )+1\\ \\ Where, \\ \\Amplitude=a=3\\ \\Period= \frac{2\pi}{b}=\frac{2\pi}{3}\ \ \\Phase \ shift= \frac{c}{b}= -\frac{\pi}{2}\times\frac{1}{3}= -\frac{\pi}{6} \\ \\ Vertical\ shift= d= 1\\ \\ Graph: \\ \\

у (3) 5 -п -2ry/3 -/3 о 3 23 П -3

\\ (4) \\ y=\frac{1}{2}\cos\left ( 3\theta+\frac{\pi}{6} \right )-1\\ \\ Where, \\ \\Amplitude=a=\frac{1}{2}\\ \\Period= \frac{2\pi}{b}=\frac{2\pi}{3}\ \ \\Phase \ shift= \frac{c}{b}= -\frac{\pi}{6}\times\frac{1}{3}= -\frac{\pi}{18} \\ \\ Vertical\ shift= d=- 1\\ \\ Graph: \\ \\

y (4) 2 -1 -11/2 -TI/3 -TI/6 0 T/6 TI/3 TI/2 -2

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