Given N(0,1), find: A) P(Z < 2.16 OR Z > 4.13) = 0.9842 Keep your answer...
Given N(0,1), find: A) P(Z < - 3.35) * Keep your answer in 4 decimal places. B) P(Z < 0.89) * Keep your answer in 4 decimal places. Given N(0,1), find: A) P(Z > - 2.65) = Keep your answer in 4 decimal places B) P(Z > 1.81) Keep your answer in 4 decimal places
4.28 If Z ~ N(0,1), find the following probabilities: a. P(Z <1.38) b. P(Z > 2.14) c. P(-1.27 <Z<-0.48)
1) Suppose that X ∼ N(0,1) find: P(X<=1.36) Round your answer to the nearest thousandth. 2) Suppose that X ∼ N(0,1) find: P(|X-0.9|>=1.35) Round your answer to the nearest thousandth. 3)Suppose that X ∼ B(8, 0.25). Calculate p(X=1) Round your answer to the nearest thousandth. 4) Suppose that X ∼ B(10, 0.23). Calculate P(X ≥ 7) Round your answer to the nearest thousandth. 5)Suppose that X ∼ U(-5, 10). Find the P(-2 ≤ X ≤ 5) Round your answer to...
3. Let Z be a continuous random variable with Z-N(0,1). (a) Find the value of P(Z <-0.47). (b) Find the value of P(Z < 2.00). Note denotes the absolute value function. (c) Find b such that P(Z > b) = 0.9382. (d) Find the 27th percentile. (e) Find the value of the critical value 20.05-
Find P(Z < 1.3). Round your answer to 4 decimal places.
Plz solve the problem by using MATLAB and show the code Given Z ~ N(0, 1) use Matlab to calculate a value c such that P(Z > c) answer to three decimal places. 0.115. Give your Given Z ~ N(0, 1) use Matlab to calculate a value c such that P(Z > c) answer to three decimal places. 0.115. Give your
a) Find a z0 such that P(z > z0) = 0.0250. (Round your answer to two decimal places.) b) Find a z0 such that P(z < z0) = 0.8944. (Round your answer to two decimal places.)
Find C(n, x)pxqn − x for the given values of n, x, and p. (Round your answer to four decimal places.) n = 6, x = 4, p = 1/3
Find C(n, x)pxqn − xfor the given values of n, x, and p. (Round your answer to four decimal places.)n = 9, x = 5, p = 14
(a) Find a z0 such that P(z > z0) = 0.0287. (Round your answer to two decimal places.) z0 = (b) Find a z0 such that P(z < z0) = 0.9099. (Round your answer to two decimal places.) z0 =