Given | |
X bar | 101.9 |
μ0 | 105 |
S | 5.8 |
n | 35 |
a)
No, because n >= 30
Hypothesis : | α= | 0.05 | ||
df | 34 | n-1 | ||
Ho: | μ = μ0 | |||
Ha: | μ not = μ0 | Two tailed | ||
t Critical Value : | ||||
tc | 2.032244509 | T.INV.2T(alpha,df) | TWO | |
Rejection region: | ||||
ts | < for - | tc | TWO | To reject |
ts | > for + | tc | TWO | To reject |
b)Test : | ||||
ts | -3.16 | (X bar-μ )/(S/SQRT(n)) | ||
P value : | ||||
P value | 0.003288849 | T.DIST.2T(-ts,df) | TWO | |
Decision : | ||||
P value | < | α | Reject H0 |
c)
d)
P value = 0.0033
0.002 < P value < 0.005
e)
P value < 0.05, Reject H0
To test Ho: u = 105 versus Hy: # 105 a simple random sample of size...
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