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To test Ho: u = 105 versus Hy: # 105 a simple random sample of size n= 35 is obtained. Complete parts a through e below. Clic

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Answer #1
Given
X bar 101.9
μ0 105
S 5.8
n 35

a)

No, because n >= 30

Hypothesis : α= 0.05
df 34 n-1
Ho: μ​ = μ0
Ha: μ​ not = μ0 Two tailed
t Critical Value :
tc 2.032244509 T.INV.2T(alpha,df) TWO
Rejection region:
ts < for - tc TWO To reject
ts > for + tc TWO To reject
b)Test :
ts -3.16 (X bar-μ )/(S/SQRT(n))
P value :
P value 0.003288849 T.DIST.2T(-ts,df) TWO
Decision :
P value < α Reject H0

c)

B. Q

d)

P value = 0.0033

0.002 < P value < 0.005

OD. If 1000 random samples of size n = 35 are obtained, about 3 samples are expected to result in a mean as extreme or more e

e)

P value < 0.05, Reject H0

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