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On a certain day in class, 45% of the students were wearing jeans. Also on the same day, 28% of the students were wearing jea
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Answer #1

Probability that a student is wearing jeans = 45%/100% = 0.45

Probability that a student is wearing jeans and t-shirt = 28%/100% = 0.28

Probability that she/he is also wearing a t-shirt given she/he is wearing a pair of jeans = ( Probability that a student is wearing jeans and t-shirt \small \div Probability that a student is wearing jeans)

Probability that she/he is also wearing a t-shirt given she/he is wearing a pair of jeans =(0.28 \small \div 0.45) = 0.6222

Answer: 0.6222

[ Note : if we want answer in percent multiply 100%

so, in percent the answer is 62.22% ]

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