46.(a)
Mass of Ra-226, m = 1.6 g
Molar mass of Ra- 226, M = 226 g
Number of nuclei present in m g of Ra-226 is N = m NA/M = 1.6 x 6.023 x 1023/226 = 4.26 x 1021
Half life of Ra-226 is t1/2 = 1600 years = 5.04 x 1010 s
Decay constant, λ = 0.693/ t1/2 = 0.693/5.04 x 1010 = 1.38 x 10-11 s-1
Activity of the sample of Ra-226 is R = λ N = 1.38 x 10-11 x 4.26 x 1021 = 5.88 x 1010 Bq
Activity of the sample of Ra-226 is R = 5.88 x 1010 Bq
59. (b)
Initial activity of Ra-226 is R0 = 4.0 x 105 Bq
Molar mass of Ra- 226, M = 226 g
Decay constant of Ra-226, λ = 1.38 x 10-11 s-1
Initial activity, R0 = λ N0
Initial number of atoms present, N0 = R0 / λ = 4.0 x 105 /1.38 x 10-11 = 2.89 x 1016
Initial mass of the sample, m0 = M N0 / NA = 226 x 2.89 x 10 16 /6.023 x 1023 = 1.08 x 10-5 kg = 1.08 x 10-2 g
Initial mass of the sample, m0 = 1.08 x 10-2 g
( C )
Activity after t years is R = R0 e-λt
Decay constant, λ = 0.693/ t1/2 = 0.693/1600 = 0.000433 year-1
R = 4.0 x 105 x e-0.000433 x 57 = 3.90 x 105 Bq
Activity after 57 years, R = 3.90 x 105 Bq
46. (a) Calculate the activity R of 1.69 of 226Ra. (Note: A = 2 N.). Answer...
46. (a) Calculate the activity R of 3.35g of 226Ra. (Note: A. = 1 N.). Answer to 3SigFigs in Bq,