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Score: 0.6 of 1 pt 3 of 9 (9 complete) 6.2.5 Given a normal distribution with p = 100 and a = 10, complete parts (a) through whats d
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Answer #1

H = 100,0 = 10 d.) P(X1<x< X2) = 0.90 T- X1 100 => PG 10 X2 – 100 10 = 0.90 0 => P(Z1 <2<Z2) = 0.90 as we know standard norma

Ans:90% of the values are greater than 83.60 and less than 116.40

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