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Question 16 8 pts A food snack manufacturer samples 20 bags of pretzels off the assembly...
please help with number 14 manufacturer samples 11 bags of pretzels off the assembly line and...
please help with number 14
manufacturer samples 11 bags of pretzels off the assembly line and weighs their contents. If the sample mean is 15.2 oz. and the sample 0.50 oz., find the 95% confidence interval of the true mea 95% confidence interval of the true mean. X=15.2,0-2,5o, noll 2 A) 15.0<u< 15.4 B) 12.9<x< 17.5 1 74.4 Luz 14.9<u< 15.5 D) 14.1 Su< 16.3 C 15.2 -1. 90 <us 15.a +auG ) > 15.2 -0.30-14.94 14) The winning team's...
1) A study of 100 professors showed that the time they spent on the average in...
1) A study of 100 professors showed that the time they spent on the average in creating test questions was 20.0 minutes per question. The standard deviation of the population is 1. Which of the following is the 90% confidence interval for the average number of minutes it takes to create a test question? a) (18.36, 21.64) B)(19.74, 20.26) c)(19.84, 20.16) D)(19.88, 20.12) 2) 1) A previous analysis of paper boxes showed that the standard deviation of their lengths is...
Essay type Questions Chapter 8 1. Packages of sugar bags for Sweeter Sugar Inc. have an...
Essay type Questions Chapter 8 1. Packages of sugar bags for Sweeter Sugar Inc. have an average weight of 16 ounces and a standard deviation of 0.24 ounces. The weights of the sugar bags are normally distributed. What is the probability that 16 randomly selected packages will have an average weight less than 15.97 ounces? 2. The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.0 inches and a standard deviation of 0.98 inches....
Question 8 2 pts Find the 99% confidence interval for the difference between two population proportions...
Question 8 2 pts Find the 99% confidence interval for the difference between two population proportions given the following information from independent samples: Sample 1: proportion p = 0.40. = 93 Sample 2: proportion p2 = 0.50, n2 = 86 O (-0.325,0.015) O 1-0.291,0.091) O (-0.179.-0.021) O (-0.298,-0.002) O (-0.417.0.317)
Question 9 20 pts Assume that a sample is used to estimate a population proportion p....
Question 9 20 pts Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places. 95% confidence; n = 396 x = 48 Question 10 20 pts Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Of 150 adults selected randomly from one town, 30...
Please answer all 3 questions 8. 7. Question 9 1 pts Assume that the data has...
Please answer all 3 questions
8.
7.
Question 9 1 pts Assume that the data has a normal distribution and the number of observations is greater than fifty. Find the critical z value used to test a null hypothesis. a=0.05 for a test of the hypothesis that the mean is greater than or equal to 98. 0 -2.326 0 -1.960 0 -1.645 O +1.645 O 1.960 Find the appropriate critical value (either Za/2 or ta/2) Confidence level = 99% and...
10. (16 pts) The mean waiting time at the drive-through of a fast-food restaurant was 84.3...
10. (16 pts) The mean waiting time at the drive-through of a fast-food restaurant was 84.3 seconds last year. The manager wants to know whether the mean waiting time is reduced. She randomly selects a sample of customers and their waiting times are as follows: 108.5 67.4 58.0 75.9 65.1 80.4 95.5 86.3 70.9 72.0 What is the population? What is the sample? At the α = 0.05 level of significance, determine whether there is evidence that the...
Question 18 9 pts Based on a sample of size 19, a 98% confidence interval for...
Question 18 9 pts Based on a sample of size 19, a 98% confidence interval for the mean score of all students, p. on an aptitude test is from 79.2 to 94.8. Find the margin of error Question 19 9 pts A group of 75 randomly selected students have a mean score of 25.2 on a placement test. Nationwide, the standard deviation of all students taking the test is 27. This sample data is used to calculate a 90 percent...
Please answer all Question 36 1 pts A shipping firm suspects that the mean lifetime of...
Please answer all
Question 36 1 pts A shipping firm suspects that the mean lifetime of the tires used by its trucks is less than 35,000 miles. To check the claim, the firm randomly selects and tests 54 of these tires and gets a mean lifetime of 34,570 miles with a standard deviation of 1200 miles. At a = 0.05, test the shipping firm's claim. test statistic -2.63; critical value = -1.645; do not reject Ho: There is sufficient evidence...
Question 8 1 pts To help consumers assess the risks they are taking the Food and...
Question 8 1 pts To help consumers assess the risks they are taking the Food and Drug Administration (FDA) publishes the amount of nicotine found in all commercial brands of cigarettes. A new cigarette has recently been marketed. The FDA tests on this cigarette gave a mean nicotine content of 28.5 milligrams and standard deviation of 2.8 milligrams for a sample of n = 9 cigarettes. The FDA claims that the mean nicotine content exceeds 31.7 milligrams for this brand...
please help with number 14
manufacturer samples 11 bags of pretzels off the assembly line and weighs their contents. If the sample mean is 15.2 oz. and the sample 0.50 oz., find the 95% confidence interval of the true mea 95% confidence interval of the true mean. X=15.2,0-2,5o, noll 2 A) 15.0<u< 15.4 B) 12.9<x< 17.5 1 74.4 Luz 14.9<u< 15.5 D) 14.1 Su< 16.3 C 15.2 -1. 90 <us 15.a +auG ) > 15.2 -0.30-14.94 14) The winning team's...
Question 8 2 pts Find the 99% confidence interval for the difference between two population proportions given the following information from independent samples: Sample 1: proportion p = 0.40. = 93 Sample 2: proportion p2 = 0.50, n2 = 86 O (-0.325,0.015) O 1-0.291,0.091) O (-0.179.-0.021) O (-0.298,-0.002) O (-0.417.0.317)
Question 9 20 pts Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places. 95% confidence; n = 396 x = 48 Question 10 20 pts Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Of 150 adults selected randomly from one town, 30...
Please answer all 3 questions
8.
7.
Question 9 1 pts Assume that the data has a normal distribution and the number of observations is greater than fifty. Find the critical z value used to test a null hypothesis. a=0.05 for a test of the hypothesis that the mean is greater than or equal to 98. 0 -2.326 0 -1.960 0 -1.645 O +1.645 O 1.960 Find the appropriate critical value (either Za/2 or ta/2) Confidence level = 99% and...
Question 18 9 pts Based on a sample of size 19, a 98% confidence interval for the mean score of all students, p. on an aptitude test is from 79.2 to 94.8. Find the margin of error Question 19 9 pts A group of 75 randomly selected students have a mean score of 25.2 on a placement test. Nationwide, the standard deviation of all students taking the test is 27. This sample data is used to calculate a 90 percent...
Please answer all
Question 36 1 pts A shipping firm suspects that the mean lifetime of the tires used by its trucks is less than 35,000 miles. To check the claim, the firm randomly selects and tests 54 of these tires and gets a mean lifetime of 34,570 miles with a standard deviation of 1200 miles. At a = 0.05, test the shipping firm's claim. test statistic -2.63; critical value = -1.645; do not reject Ho: There is sufficient evidence...
Question 8 1 pts To help consumers assess the risks they are taking the Food and Drug Administration (FDA) publishes the amount of nicotine found in all commercial brands of cigarettes. A new cigarette has recently been marketed. The FDA tests on this cigarette gave a mean nicotine content of 28.5 milligrams and standard deviation of 2.8 milligrams for a sample of n = 9 cigarettes. The FDA claims that the mean nicotine content exceeds 31.7 milligrams for this brand...
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