Given, at 500C,
Neutral pH = 6.62
pH = - log [H3O+]
6.62 = - log [H3O+]
[H3O+] = 10-6.62
[H3O+] = 2.40 x 10-7 M
Alternate approach:
Gven Kw = 5.8 x 10-14
Note: Kw = [H3O+] [HO-]
A neutral solution has [H3O+] = [HO-]
Hence [H3O+] = [HO-] = (Kw)1/2
[H3O+] = (5.8 x 10-14)1/2
[H3O+] = 2.40 x 10-7 M
SIMULATION Kw, Temperature, and Neutral pH 14.0 Temperature: Basic 50 °C Basic 1 → Calculate Clear...
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