Question

Hi, I need to solve this wood truss using method of joints to find every force for each member and whether it is in tension or compression. I also need to determine the reaction forces at both pinned connections.

SY - TY= 1940 * 3,740 * 6Y - 5Y - 3,740 * 3,740 44 = 3Y = # 3,740 2Y = 3,740 * IY = 3,740 # 1,940 * > 4'-0" 1.4'-0" 1.4'-0". 4'-0" 4'-0" 4'-0" .4'-0" 28'-0"

Answer 1

1990 3140 3140 1940. 3740 3740 3740 3740 u D H I 4 1875 VM B F g A n RB В RA tan o = BM BN. RA + Rp = 26.320 BM = Bn tom (8.50574) 50.59 EMAIO Rox (20) 3,740 (4+8+12+16+20) + 1,940 (24) - 4x 1,940. RB = 13,160 RA = 13, 160 1,940. 5): 88.50574 O=kay( 5:1875 FMn. joint N en FEN Fmn ane = Fon. FAN Sin O= 1,940 Fer 12,971,9 Comprension) Pmw = 13,116,2 | Creusion) Fem. jont B Fom = 13,160 FBN =12,911.9 FAB = 12,971.9. FKB Rp = 13,160 CS Scanned with CamScanner

ty pont m 3740 70.548 FML к B S 2o > FAN a 13 116.2 FBM = 13160 FEM. Fore Sino FILM Sing 13116.2 Smo - 3740 +13160 0.1478 Fome 0.1449 Fiem - -7481,3. (FML - FILM ) = 50617.7 FML caro + From Corp = 13116.2 Cin o 6.989(fine + Fmk) =12978.13 FML TEME = 13116.4 506 H. T & Fem tink=3116.4. Enk = -18750.65 (compressions) FML =31867.05 (Tensions) joint L 3740. ful FM=51867.05. FIL. 31867.05 Coso = FEL ano. ~3740 + 31867.05 Sino + FIL- 31867.05 no FEC = 31864.05 (torsion) FCL = 3740 (comprenion) CS Scanned with CamScanner

E E 8 jont k FILE 3740 18750.65 1 mich LI=1.1956. 0= 16.000 Fran K. PREB 212 97.9 FIL Sin 16.64 + 3140 + 18450.65 = FER =-78540,5 Gension) + Fak = 187500.650 €12971.9 FIK Cos 16.64 Fuk = 110263.0 (compression 3740 jont-I HI JO 16.649 FIL 1867.05 & FIK =78560.5 Ful THI Coro + Ful Cos 16.64 = 78540.5 cos (16.64) + 31861.05 Cone (8,5) 106768.469 cos(8.5) FHZ 70.958 Faz 3740 + FHI Sino Fursm (16.6h) - 78540.5 Sin (16.64) - 31867.05 sm 8.50 Fupi(9'5) - Fue Smsl1464) = 30940.89. Ful THI Sin 28.5) - 30940182. Sm (16.64) ( cos (8.6) FHI 70,95PX =106Y68.469. EAI Sin (8.5) ~30940.82 sin (16.64) as (8.5) FH2 +3.34 FAI sin 8.5 - 30394012 2X 3.34 =106768.469. 1.482 FHI = 1121928.8 FHI = 757036.977 Gension) cs Scanned with CamScanner

FuL = 282711. Tension) 9740 jont H FUE → FHLI =75703 6.97 Full THE = 157036.97 (Tension) FHG = 3740 (compression) E 1:999 1.5501 FEG. F 3740. 20 jont G. Fin. Fins 282711 36.17 FEE 16.644 E Fak = 110263.05 FAQ 7.999 FEL Sim 36.17 - 3740 +282111 Sin 16.64 fm "( 2.999)-36.76 FED = 728994, Fags fl28994 cos 686.47)) 110263.05 + 282711 Cos (1664) =o. (Compresson) Fan 3740 joint FDE 36.77° 1.17 FAE = 157036.27 FAE Fen=128994 FDE CI (8.5) + Pre as (6.77) 128994 s 36.77 + 757036 as (8.5) FAE as (16.77 ) - PoE Com (9.5) = -645390.6 FoE Sin (8.5) - 3440 FFAE Sm (36.77) + 128994 Sn (36.77) - 757036.97 Sindre Sm (8.5) & FAE Sin (36.77) = 38420.8 FDE CS Scanned with CamScanner

FAE =745390.6+ FoE Cos (85) Cos (36.77) (FOE For Sin (8.5) + FoE Cos (8.57-645390.6 6166.77) sin (36.77) = 38420.8. Sin (9.5) FOE + 0.747 cos 68.87 BE - 645190.670-747 = 3842015 FOB = 587105.32 (Tension). IFAE FAE = -8081211 (Tension 3740 jout o EDC FDE FADE FAD = 3740 bom presion foc = 587105.32 Tension 1940 joint a Ô 46.31 > Eco -587105.12 FCA FCA Sm 46:31 - 1940-587185.92 sm (1.5) 2o. FCA = 122695-6 Compression .) CS Scanned with CamScanner