Question
A generator connected to an RLC circuit has an mms voltage of 160 V and an ms current of 36 mA

Part A If the resistance in the circuit is 3.1 kN and the capacitive reactance is 6.7 kN , what is the inductive reactance of
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Answer #1

impedence of the circuit, Z = V/i = 160/(36*10-3) = 4444.44 ohm

Also,

Z2 = R2 + (XL - XC)2

(XL - XC)2 = Z2 - R2

(XL - 6700)2 = 4444.442 - 31002

(XL - 6700)2 = 10143046.91

(XL - 6700) =  ± sqrt(10143046.91)

(XL - 6700) =  ± 3184.81

considering the positive sign

XL = 9884.8 ohm

considering the negative sign

XL = 3515.19 ohm

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