Question

For the equation 2x2 + 2y2 - 12x + 8y - 24 = 0, do the following. (a) Find the center (h,k) and radius r of the circle. (b) Graph the circle. (c) Find the intercepts, if any. (a) The center is (Simplify your answer. Type an ordered pair.) The radius is ra (Simplify your answer.) (b) Use the graphing tool to graph the circle. Click to enlarge graph X (c) Find the intercepts, if any. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. The intercept(s) is/are (Simplify your answer. Type an ordered pair. Use a comma to separate answers as

Answer 1

Given equation is 여 2x² + 2y2_19x tay - 24 = 0 2132-62) + 2 (y?+4y) - 24 = (22-6X) + (y?+94) - 12 (xc²-6*+9-9) + (y² + 4y +4-4) 12 20 (30-6x+9) + (y + 4y +4) -12 -13 = 0 + (9+2) 2 (5x+3)² + (y+22=5² conpare with (06-b)2 + (yak²= q² a a here, h = 3, K = -2, 95 (а I centre (h, k) = (3,-2) radius r=a=5 b in For x-intercepts, (3-2) g=0. 5 (x-3)2 + += 25 (0-3)2 = 21 x = 3 +591 x=0. =) For y-intercepts, 9 + (1+2) 2 (4+2)2 = 16 -) 9+2=74 = 25 y = 2,-6