1) A sample of 513 L of Kr gas at 225 K in a container pressurized...
1) A sample of 513 L of Kr gas at 225 K in a container pressurized at 1.562 atm is compressed to 227.4 L with a pressure of 2.08 atm. The temperature needed to maintain these conditions would be ______________ K.
2) For the reaction shown below, write the total ionic equation. Then write the net ionic equation.
CrBr6 (aq) + 3 CaS (aq) -----------------------------> CrS3 (s) + 3 CaBr2 (aq)
3) If 1.776 kg of CrBr6 was dissolved in 4011 mL of water the molar concentration of the CrBr6 solution would be ________
Homework Answers
Request Answer!
We need at least 10 more requests to produce the answer.
0 / 10 have requested this problem solution
The more requests, the faster the answer.
Add Answer to:
1) A sample of 513 L of Kr gas at 225 K in a container
pressurized...
A 10.33 mol sample of krypton gas is maintained in a 0.7797 L container at 301.0...
A 10.33 mol sample of krypton gas is maintained in a 0.7797 L container at 301.0 K. What is the pressure in atm calculated using the van der Waals' equation for Kr gas under these conditions? For Kr, a = 2.318 L’atm/mol and b = 3.978x10-2 L/mol. atm
A 9.450 mol sample of krypton gas is maintained in a 0.8100 L container at 300.1...
A 9.450 mol sample of krypton gas is maintained in a 0.8100 L container at 300.1 K. What is the pressure in atm calculated using the van der Waals' equation for Kr gas under these conditions? For Kr, a = 2.318 L2atm/mol2 and b = 3.978×10-2 L/mol. atm
A 10.13 mol sample of krypton gas is maintained in a 0.7517 L container at 297.2...
A 10.13 mol sample of krypton gas is maintained in a 0.7517 L container at 297.2 K. What is the pressure in atm calculated using the van der Waals' equation for Kr gas under these conditions? For Kr, a = 2.318 L2atm/mol2 and b = 3.978×10-2 L/mol.
A 10.83 mol sample of argon gas is maintained in a 0.7598 L container at 295.6...
A 10.83 mol sample of argon gas is maintained in a 0.7598 L container at 295.6 K. What is the pressure in atm calculated using the van der Waals' equation for Ar gas under these conditions? For Ar, a = 1.345 Llatm/mol2 and b = 3.219x10-2 L/mol. atm USE LIIC CICICULUS LU al USS IITIPUI lalil va The rate of effusion of H2 gas through a porous barrier is observed to be 1.17 x 10-4 mol/h. Under the same conditions,...
A container containing 6.19 L of a gas is collected at 244 K and then allowed...
A container containing 6.19 L of a gas is collected at 244 K and then allowed to expand to 23.4 L. What must the new temperature be in order to maintain the same pressure? Express your answer in units of K. You do not need to enter the unit. When 16.8-grams of an unknown compound is placed in 0.176-kg of benzene, the freezing point is changed by 1.93oC. The value of Kf= 4.90oC/m for benzene. Determine the molar mass of the...
A 1.55-mol sample of nitrogen gas is maintained in a 0.730-L container at 292 K. Calculate...
A 1.55-mol sample of nitrogen gas is maintained in a 0.730-L container at 292 K. Calculate the pressure of the gas using both the ideal gas law and the van der Waals equation (van der Waals constants for N2 are a = 1.39 L2atm/mol2 and b = 3.91×10-2 L/mol). Pideal gas equation = ______ atm Pvan der Waals =_____ atm
w4. 1a) For the following reaction, 0.275 moles of hydrochloric acid are mixed with 0.372 moles of oxygen gas. hydrochlo...
w4.
1a) For the following reaction, 0.275 moles of
hydrochloric acid are mixed with
0.372 moles of oxygen gas.
hydrochloric acid (aq) + oxygen (g) --> water (l) + chlorine
(g)
What is the formula for the limiting
reagent?
What is the maximum amount of water that can be
produced? (answer in moles)
1b) An iron nail rusts when exposed to oxygen.
For the following reaction, 0.343 moles of
iron are mixed with 0.127 moles
ofoxygen gas.
iron (s) +...
Question 1 (a) Use the ideal gas equation to calculate the pressure (in atm) of 2.40 mol of krypton (Kr) at 455 K in a 4.50 L vessel. (b) In a 16.3 L vessel, the pressure of 2.40 mol of Kr at 455 K...
Question 1 (a) Use the ideal gas equation to calculate the pressure (in atm) of 2.40 mol of krypton (Kr) at 455 K in a 4.50 L vessel. (b) In a 16.3 L vessel, the pressure of 2.40 mol of Kr at 455 K is 5.50 atm when calculated using the ideal gas equation and 5.40 atm when calculated using the van der waals equation of state (Note: a=5.121 and b = 0.0106). Why is the percent difference in the...
According to the ideal gas law, a 9.843 mol sample of argon gas in a 0.8425 L container at 502.0 K should exert a pressure of 481.3 atm
Hint: % difference = 100×(P ideal - Pvan der Waals) / P idealAccording to the ideal gas law, a 9.843 mol sample of argon gas in a 0.8425 L container at 502.0 K should exert a pressure of 481.3 atm. By what percent does the pressure calculated using the van der Waals' equation differ from the ideal pressure? For Ar gas, a =1.345L2 atm/mol2 and b = 3.219×10-2 L/mol.
1. A sample of gas with an initial volume of 28.4 L at a pressure of...
1. A sample of gas with an initial volume of 28.4 L at a pressure of 735 mmHg and a temperature of 309 K is compressed to a volume of 14.5 L and warmed to a temperature of 377 K .What is the final pressure of the gas? 2. A cylinder with a moveable piston contains 216 mL of nitrogen gas at a pressure of 1.29 atm and a temperature of 292 K .What must the final volume be for...
A 10.33 mol sample of krypton gas is maintained in a 0.7797 L container at 301.0 K. What is the pressure in atm calculated using the van der Waals' equation for Kr gas under these conditions? For Kr, a = 2.318 L’atm/mol and b = 3.978x10-2 L/mol. atm
A 10.83 mol sample of argon gas is maintained in a 0.7598 L container at 295.6 K. What is the pressure in atm calculated using the van der Waals' equation for Ar gas under these conditions? For Ar, a = 1.345 Llatm/mol2 and b = 3.219x10-2 L/mol. atm USE LIIC CICICULUS LU al USS IITIPUI lalil va The rate of effusion of H2 gas through a porous barrier is observed to be 1.17 x 10-4 mol/h. Under the same conditions,...
w4.
1a) For the following reaction, 0.275 moles of
hydrochloric acid are mixed with
0.372 moles of oxygen gas.
hydrochloric acid (aq) + oxygen (g) --> water (l) + chlorine
(g)
What is the formula for the limiting
reagent?
What is the maximum amount of water that can be
produced? (answer in moles)
1b) An iron nail rusts when exposed to oxygen.
For the following reaction, 0.343 moles of
iron are mixed with 0.127 moles
ofoxygen gas.
iron (s) +...
Most questions answered within 3 hours.
-
Calculate the pH of each of the following solutions.
0.50 M HBr
3.1×10−4 M KOH
4.2×10−5...
asked 1 hour ago -
For the year ended December 31, Depot Max’s cost of merchandise
sold was $85,600. Inventory at the...
asked 1 hour ago -
Week 10 - Professional Memo Assignment
Professional Memo Assignment
Your mission for this week, should you...
asked 1 hour ago -
Write a Python program that stores the data for each
player on the team, and it...
asked 1 hour ago -
In
the last 3 months, mike never knows when he is going to get his
allowance...
asked 2 hours ago -
Is Ca(OH)2 a Bronsted base, Lewis base, or both? Why?
asked 1 hour ago -
1A- Why don’t voters complain about U.S. tariffs on imported
sugar?
Because sugar is only a...
asked 2 hours ago -
Cash Payback Period
Primera Banco is evaluating two capital investment proposals for
a drive-up ATM kiosk,...
asked 2 hours ago -
Create a button in Swift (Xcode) that will create a charge,
create a charge using Stripe's...
asked 2 hours ago -
The reaction rate of CO and NO2 in the reaction
CO(g) + NO2(g) → CO2(g) +...
asked 2 hours ago -
Imagine that a chemist puts 6.40 mol each of
C3H8 and O2 in a 1.00-L container...
asked 2 hours ago -
How much money should be invested today in order to have $8340
at the end of...
asked 2 hours ago