Question

>= ? 2M An object of mass 3M, moving in the +x direction at speed Do, breaks into two pieces of mass M and 2M as shown in the figure. If o, = 65.0 and 02 = 23.0, determine the final velocities , and Uy of the resulting pieces in terms of vo. 3M M = ? Di = Do U2 = Uo

Answer 1

- Answer V₂ 2MV2 sin23 2M Oz - 239 3M Vo 2M V2 Cos 23 () MV, cos 65 0,= 65 MV, sin 65 This be solved can using law of conservation of linear momentum. Since the the '+x-direction in mass Object with 2M moves conservation of momentum in x-axis according to (Pi) (Pf) 3 M vo 2M VACOS (23) + MV, Cos(65) Vi COS 65 +2 V2 Cos 23 3vo =>. 0.423 V + 1-84 V2 3 Vo Along the y-axis (PDy - (Pfly Y 2M V₂ sin 23 MN, sin 65

2MV, sin 23 MV, sin 65 V2 sin 23 V sin 65 V sio 23 sin 65 2 V 0.43 72 OY V₂ 2.32 , 3 Substituting ☺ in 0 3 Vo 0.423 vi + 1. & 4 ( 2.32 V) 4-692 v 3 Vo. 3 vo =). Vi 4.692.1 زد رو vi 0.639 Vo z Substitating this in equation ☺ V22 2.32 V 2.32 x 0.639 Vo V2 To482 Vo N