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Determine the inverse Laplace transform of the function below. Se -45 s2 + 10s + 50 Click here to view the table of Laplace t

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{ se48 Question : (1) gatlost 50 Solution : Flow, the propeaties of inverse Laplace transform, we have li Fiest shifting beo12) 5 .. F(9) s Sa+245x 9 +53 +25 s ( 37 sjá ta5 uf:(a+bhe (= CPF296+6) st5-5 ( Notel 1-375)2+25 (365) 1st 512425 (3+594+25 F(8) d Fea1] = Iç Fi(3+5).–F 1945) { F1(8+51) – I{ FE(3+5) Il Pan Fi(+ 92 Ft-3)? ai mop Fi(2+ abatiF49)), by linearity pr14) = =** [ zil #583 - 2375] ēst [ Cos 15t) – Sin(58)] Il 9 249* Coslat) and om te gaan? = Si (at). ds F1933 = ēst ests Colsees Setlost56 १) .: - flt-4) - U(t-4) Now from equation (8), we have $(t=4) = otty Cas5(+-4) - Sin5t-4) - Fit-y) = 2 -) { c() Hence we have 8 ?비 Xt09+50 넚 SIE-) } cas(ste-- 3.5+ (s(e-i), t >> = ,t<4 오 회 95 Sat) 왱 E-M) Co(s(==)) - Sp(s(E-) 3. Ult-4)

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