Question

اولی ما نك رعو Asst. Lec. Murtadha S. Mohammed Thermodynamics/18, years Example: ا اے One kg of a perfect gas is compressed from 1.1 bar, 27C° according to law PV 1.3 = C until the pressure is 6.6 bar find the heat flow to or from the system when the gas was than M=30kg/k mol,Cp = 1.75 kJ / kg. K, C =1.472 kJ/kg.K. هے :Solution Cp 1.75 1.188 + n The

Answer 1

C, dT Q - PdV du CdT+ Pav Q dT G = Cot Pav dT pytrg=c PV = nRT MRT 13 - 6 TV.3 = 6 U nR 0.3-1 10.3. 1+T (0:3) v dve AT V+ 0.3T voor dT 0.3 الم ро dv AT 0.3T Co - PV theat capacity 0.3T 0.37 (x - DRF - 1.4 72 kJ/kg . K - 1000 , 8.314 = 1.472-01277=1-195kJ/K. 1000 X 8.314x300 38 1.1x100 3 3 558m V=NRI R = (P, vlez y los L 713 XV. = 0.1905 m² P2 P. Ta= 6²6 X 10 xal 905 = 45.36 2.453-623K nh 1004 x 8.314 39 Heat flow to the system = C. AT 1.195 kJ/k. x (453.623-300) K = 183.56 kJ (Anowas)