Question

Marks] c. Your company desirous of meeting a deadline gave you two circuit diagrams as shown in figures 2 and 3 to implement in a particulate section in a device. You have the choice to choose one of them for implementation. The only condition is to use superposition theorem to determine the current flowing through the branch AB. Give reasons for your choice. A 7 v 5v 35 B Fig 2 4 Ohms 13 Ohms A 10 Volts 100 B Fig 3 AP [7 Marks] QUESTION THREE [Total: 20 Marks Q. An electrical engineer wos given a contract to design a device with the following specifications: a source voltage of 240 volts and three resistors with 1092, 209 and 302 marks on them respectively. This engineer subcontracted this job to you, and instructed you to connect these resistors in series and then in parallel. With your knowledge in circuit analysis, determine the values of the resistance and the current in each scenario. AP (5

Answer 1

1) To apply superposition theorem, we need atleast two independent power sources So, among the figures 2 and 3; figure a is having two voltage sources, :. So, choosen circuit will be from big.a у 5V 7V 551 २.2 122 B - Applying Superposition theorem :- i) 7V is acting is acting ; 5V → shortened 2 ok 70 52 2.2 ie Nodal analysis :- V-7 + + V 2 O 5 NOV-70 + 2V + 5V lo CS Scanned with CamScanner

177 OL = V- OL 17 14 A "? >160 TO 5217 LI 5V acting ; 7V → shortened 3 V Tiz AS ak لم JR 2.12 1-2 Nodal Analysu ? V-5 V 0 = t + >llo ३ 5V - 257 2V + 10V 02 10 17 V = 25. V=25/17 ,ا V 5 95 5x17 5 A 17 CS Scanned with CamScanner

Total curment flowing through AB is Inet i tiz 14 17 + ply 1.117 Amp Init 19 17 = 2) We have V=240 V resistors = 100, 201, 302 Case Ii Resistors in Series î M los 20:12 30.12 240. VT In series net resistance is equal to Sum of all resistances 10 f. 20. +30 Net resistance ܐ 60 Current, i = 240 60 i= 4 Amp. CS Scanned with CamScanner

case 2: Resistors in parallel. 300 Slor Zaor 24ov Net resistance - = + t 10 20 30 Rnet 6 + 3+.2 60 il Go Rret Go Rnet 2 11 60 is Net resistane Current, V Rret i = 240 60/4 { = 240 X 11 60 { = 44 Amp. CS Scanned with CamScanner

Thank You...!!!