Let z = x2 + y2 be the surface, and x = -1+t, y = 2+t, z = 2t + 7 be the line. Find the incorrect answer in the following Select one: The acute angle between tangent to the surface and the given line at the -1 4 point (0,3, 9) is į – cos V537 The normal to the surface at the point (0,3, 9) is 6 j - k. The line is normal to the surface. The...
Let f(x, y) = x²y + 5yº. At the point (1, -2), which one is incorrect about the behaviour of the function f: Select one: f(x, y) is decreasing at the rate of 4 units per unit increase in X. f(x, y) is increasing at the rate of 61 units per unit increase in y o the slope of the surface Z = f(x,y) in the y, direction is 61 f(x,y) is increasing at the rate of 4 units per...
Consider the following. z = x2 + y2, z = 36 − y, (6, -1, 37) (a) Find symmetric equations of the tangent line to the curve of intersection of the surfaces at the given point. x − 6 12 = y + 1 −2 = z − 37 −1 x − 6 1 = y + 1 12 = z − 37 −12 x − 6 = y + 1 = z − 37 x − 6 12 =...
Let F(r, y, z)(z4+ 5y3)i + (y2 surface of the solid octant of the sphere x2+yj2 + 22 = 9 for x> 0, y> 0 and z> 0 )j+ (3z + 7)k be the velocity field of a fluid. Let B be the Determine the flux of F through B in the direction of the outward unit normal Let F(r, y, z)(z4+ 5y3)i + (y2 surface of the solid octant of the sphere x2+yj2 + 22 = 9 for x>...
6 (20 pts). Let F(x, y, z) = x2 + y2 + x2 - 6xyz. (1) Find the gradient vector of F(x, y, z); (2) Find the tangent plane of the level surface F(x, y, z) = x2 + y2 + x2 - 6xyz = 4 at (0, 0, 2); (3) The level surface F(x, y, z) = 4 defines a function z = f(x,y). Use linear approxi- mation to approximate z = = f(-0.002,0.003).
Chapter 13, Section 13.7, Question 017 (a) Find all points of intersection of the line x = -2+1, y = 3 +t, z = 2t +21 and the surface z= x2 + y2 (b) At each point of intersection, find the cosine of the acute angle between the given line and the line normal to the surface. Enter your answers in order of ascending x-coordinate value. (a) (b) (x1,91,21) = (003 Edit cos 01 = ? Edit (x2, Y2, 22)...
(1 point) A parametric curve r(t) crosses itself if there exist t s such that r(t)-r(s). The angle of intersection is the (acute) angle between the tangent vectors r() and r'(s). The parametric curver (2 -2t 3,3 cos(at), t3 - 121) crosses itself at one and only one point. The point is (r, y, z)-5 3 16 Let 0 be the acute angle between the two tangent lines to the curve at the crossing point. Then cos(0.997 (1 point) A...
At what point on the surface z = 2 + x2 + y2 is its tangent plane parallel to the following planes? (a) z = 6 (x, y, z) = (b) z = 6 + 4x − 12y (x, y, z) =
Consider the following. w = In(x2 + y), x = 2t, y = 5 - t (a) Find af by using the appropriate Chain Rule. (b) Find by converting w to a function of t before differentiating. -/1 POINTS LARCALC11 13.R.054. Differentiate implicitly to find oux x2 = 9 x + y -11 POINTS LARCALC11 13.R.069. Find an equation of the tangent plane to the surface at the given point. z = x2 + y2 + 9, (1, 2, 14)
2. Given the paraboloid: z + x2 + y2 = 6. a) Find the symmetric equations of the normal line at the point (1, 2, 1). b) Find the equation of the tangent plane at the point (1, 2, 1). Simplify. c) Find the angle of inclination of the tangent plane to the xy-plane in degrees. Round to the tenths place.