Question

Consider the electric circuits below: R1 = 1.00 2: R2 = 2.00 2; R3 =3.002; R4 =4.00 2; Rs = 5.002; R Ro -A R2 Wit R5 RA ww +* 12 V Redraw the circuit on the paper that you will upload later, and simplify the schematics in steps until the circuit is represented by one equivalent resistor. 2 a) Determine the equivalent (total) resistance of the whole circuit b) Determine the potential difference across the resistor Rs c) Determine the current through resistor R4 d) Determine the total power dissipated by the circuit Indicate on the paper drawing where and how would you connect instruments to measure potential difference AV across resistor R3 and current I through R2. Indicate the name of each instrument (A.V) on it.

Answer 1

Ima Ry 2 3 > I t ㅗ R1234 23 23 Giren Ri R = 1.000, R2 = 2.000, R3=3.002 R5 R4 = = 4.002, Rg=5.00 & B= 12 V @ For equivalent resistance (total) YR12 = + k2 (:R, of R2 is in paralled) 12V VR12 = Ratri 2+1 - 3 RIXR2 2x1 Riz Rz R12 = 2 R5 Ry R12 & Rz is in series so R123 R12 + R3 = 3 + 3 = 11 12V Now R123& R4 is in parallel combination, so 173 + + 4 = 3 + ч R123 R4 44. 2 12+11 R124 R1234 R5 44 44 Now R1234 & R5 is in series combination so total equivalent resistance of the circuit 44+ 115 Reg R1234 + R5 = 44+ 5 = Req= 6.912 (6) Current in the circuit 12 = 1.74 6.91 through rusister R5 - Ig = I = 1.74 .! Pati difference across resistor Rg = V5 = Is. R5 = 1.74 x 5 = 8.7. V c) current through resistar R4 by current division law 14 = I XR123 1.74 x 11/3 19.14/8 0.83 A R123+Ru 23/3 1+ 4 d) Tatal power dissipated by circuit, p = V.I = 12x1.74 = 20.88 Watt 12V 23 23 = 12 I = Kea current flowing RI Here R3 R5 A Ammeter V Valtmeter R2 Run 카 12 V