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QUESTION 2 (a) A radioactive isotope, Pb-209, decays at a rate proportional to amount present at time t and has a half-life o

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Y+1= 4x² b) Given 23 y= Ae - 1 Differentiate equation ① with respect to x, = A.322 dy da Ae I dy 3x² da Substitute the abov
y + y3 Given y=1 when x=1 12+ 4+3 So 1 + 1 2 + 1 4 - 0 => C= 12 C =19 12 :. The required particular solution is 19 yxt x 4 3
IF = peca Solution is y (I.F) = JQc). (I-F) da te frece y secx = 1 sec²x dx tc seca-recx dx + c y seca tanate Уge Сх when a=0
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