Question

A student set up a magnetic optical bench as you saw in the video. You may assume that the positions stated already account for offsets. Please assume also that the light source and the crossed arrow target were located closest to the end of the scale marked zero. A crossed arrow target was located at position CAT using an object whose size is So. After passing through a lens having focal length located at position L, the light formed an image located on a screen at position S whose size is si. In the remaining questions, please use the following values: sp-1.50 cm, 81.00 cm, CAT 9.80 cm, S-57.6 cm. The numerical value for the object distance o is given by a. 29 cm b.28.7 cm c. 47.8 cm d. None of the offered answers. 21.0 cm

Answer 1

The magnification equation states that M = Hi/Ho = -v/u, where M is the magnification, Hi is the height of the image, Ho is the height of the object, v is the distance from the lens to the image and u is the distance of the object to the lens.

Then M = si/so = 1.5 / 1.0 = 1.5

Then 1.5 = -v / u = -57.6 / u ;

Now u = -57.6 / 1.5 = -38.4 cm

i.e ; u = -38.4 cm

So option D - None of the above .

P.S.if this helped you please like the answer.Thankyou.