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Consider the function f(x) = 4(x - 2)2/3. For this function there are two important intervals: (- 00, A) and (A, 0c) where A
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solution fex) = 4 (x-2) Note: Critical points of function fex) are either roots of f(x) = 6 feas not exists at that point Now

I cx) = 8. 1 (2-2) % fca) - 2 Now, -8 (2-2) 9 Now, for x 22 fca) Lo also for x 2 Ta zo concave down C-002) : fox) (2100) :

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