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Find the indicated probability. Round your answer to 6 decimal places when necessary. TWO fair coin are tossed. Let A be th

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Answer #1

(12)

Here let S be sample space then

S={HH,HT,TH,TT}

A={HT,TH} therefor P(A)=2/4=1/2

B={HH,TH} therefor P(B)=2/4=1/2

AnB={TH} therefor P(A and B)=1/4

P(A or B)=P(A)+P(B)-P(A and B)

=1/2+1/2-1/4 =3/4

option (D) is Correct.

(13)

Select FALSE

Because every time we roll our dice we have all six faces available so no roll is dependent on the previous roll.

But if it is drawing of card then it will be dependent.

(14)

As order of the selection does not matter therefore we have to use Combinatories.

Here we need to choose 5 numbers out of total nine numbers {1,2,3,..,8,9}

So number of possible choices is C(9,5)=126

option (D) is correct

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