Question

Light of wavelength 600 nm is incident upon a single slit with width 3.0 x 10 m. The figure below shows the pattern observed on a screen positioned 2 m from the slits. Determine the distance s. O 0.008 m O 0.002 m O 0.003 m O 0.004 m O 0.006 m

Answer 1

here, s is the distance of the second minima from the centre.

We know,

s= 2×D×/a

here, D = distance between the screen and the slit = 2 m

   = wavelength of light = 600×10^(-9) m

a = width of the slit = 3×10^(-4) m

Now, s = 2×2×600×10^(-9)/3×10^(-4)

=> s = 0.008 m

The correct option is : a) 0.008 m

Please comment if you have any doubt and like if it helps.

Happy learning.