Third option is the correct answer
NH3 will form hydrogen bonding .
Explanation :
Hydrogen bonding is a strong bond formed due to intermolecular attraction between Hydrogen and highly electronegative atoms of elements with lone pair ( mainly with N,O, F) .
Let's go through each options .
First option :
In CH4 , there are no lone pairs present in carbon moreover electronegativity difference between carbon and hydrogen is less hence it can't form hydrogen bonds .
Second option :
In HBr , although there are lone pairs of electrons present in bromine , it can't form hydrogen bonds as there are large difference in size of hydrogen and bromine atoms which makes overlapping of orbital very poor , also the difference in electronegativity of Hydrogen is not very large hence it won't form hydrogen bonds .
Third option :
In NH3 , there is one lone pair of electron present in nitrogen ( nitrogen have 5 valence electrons and only 3 are bonded with 3 hydrogen atoms). There is also a significant electronegativity difference between hydrogen and nitrogen atoms .
There is a intermolecular attraction between the lone pair and hydrogen atoms of other NH3 molecule hence forming hydrogen bonds .
Fourth option:
In H2, there won't be any hydrogen bonding as only one element (hydrogen) is present .
Therefore third option NH3 is the correct answer.
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