Question

Select your answer. We use the data in the table below and the sign test to determine whether the true median score on a certain test is significantly different from 67. 91 42 39 62 55 82 67 44 51 77 61 52 76 85 64 What is the p-value of the test? O 0.21 O none of the answers provided here O 0.79 O 0.15 O 0.18 O 0.09

Answer 1

Answer:

On the basis of the given data observation above or equal the median = 7 , below median = 7

Values (x)	Median	difference
91	62	29
42		-20
39		-23
62		0
55		-7
82		20
67		5
44		-18
51		-11
77		15
61		-1
52		-10
76		14
85		23
64		2

with the help of excel using the sign test:

tep-3:
Number of plus sign = 7
Number of minus sign = 7
n = 7 + 7 = 14

Step-4:
p-value = BINOMDIST(7, 14, 0.5, TRUE) = 0.6047
Since the p-value(0.6047) > α(0.05) (two-tailed test), we can't reject the null hypothesis H0.

so the right ans is p= 0.6047 ( Non of the answer provide here)

alternative method:

The provided number of positive signs is X+ = 7 and the number of negative signs is X = 7. (1) Null and Alternative Hypotheses The following null and alternative hypotheses need to be tested: Ho: Median of Differences = 0 Ha: Median of Differences #0 The test statistic is X = min{X+, X-} = min{7,7} = 7. (2) Rejection Region The critical value for the signficance level provided and the type of tail is X* = 2. (3) Decision about the null hypothesis Since in this case X = 7> X* = 2, there is not enough evidence to claim that the population median of differences is different than 0, at the 0.05 significance level.