Question
anyone know how to do this?
At a certain temperature, Ke = 8 for the reaction: 2NO2(g) = NO3(g) NO(g) + If 10.0 mol of NO2(g) were added to a 1.0 L vesse
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Answer #1

10.0 mol Initial concentration of NO2 - 1.0L 10. M NO₃ 2 NO2 + NO o Initial 10. M tx - 2x tx Change Equilibrium x 2 (10.–2x)

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