Question

Water flow steady through a pipe with Dia=0.75 m at point 1 and Dia= 1.5 m at point 2 as shown below. Find the velocity and the volume flow rate at the exit point.(Ywater = 9800 N/m) D-1.5 m D=0.75 m (1) water (2) Y D = 2 m 1m 0.7m SG=0.88 T 0.3m 0.5m 02 m 0.5m 0.5m S6=13.5S SG:13.55

Answer 1

To solve the given question, we must write Bernoullis equation between points 1 and 2. Later on we must calculate pressure difference using the manometer equation. This will help us extract velocity from Bernoullis equation.

Please refer to attached images for solution of given problem, do comment in case of any query. Good luck!!

* Now lette write the equation for the manometre Pi + Sp.(0:5+0:5) - Sj (0.5) P2 +8,60.5) - Sg60.5 - Ob 10:32 - Pi-P₂ sy.co.5) teb60.5) -86(1) - Sg60.5) -sbro.3 P = P2 [ Sg (0.5) teoro.] P, P2 = [ssero:5) + (13550X60-3)] P, P22 -4505 pa. .(3) Pothing ② & 6 in ① in ① we have; " (1.5-1.7) + (1₂²-16 V2² (-4505) H00 x 9,81 2x9.81 – 15422 -5.086 2 V 0.3390 Vz 0:58 223 mts velocaly at erat. How rate Q- Ap. I 2 = [X 2²x0.5622 = 1.828 m S

Notations used

Rho_b = density of blue fluid.

Rho_g: density of green fluid

Rho: density of water