Question

Using Method of sections determine the forces in members DC, HC, and HI. (Don't forget to say whether they're in tension or compression (25 pts) Ib Ib 3 ft 3 ft 3 ft EN D 2 ft. lb G H 2 ft B Ib 2 ft А. I

E = 50 lb

D = 60 lb

C = 20 lb

B = 30 lb

Answer 1

3ft 34 aft Soln 5016 Golb do E We need to find forces in member DC, he and HI X aft F - Polb Cc H eft RRE I 30 lb B eft A Consider cut cut 3 Section 3-X in figure which as shown members of truss in which forces are need to be find. ► Rgs reaction reaction force at Roller support F. for finding RFI let's taker, EMAZO (RF16) - 150x3) -LPOX4) (308) so RE*6 = 290 IRE - 48.33 lb

- Nowo, conside truss , upper part of section X-X. of – for equilibrium, Elst od 60 Foc T: 12 e {FxZO F ex Н He 9 Fhc + Fpc Coso ro FHI 44.33 ot oto G 3 3 3 ② { Fy co DHC for triangle ૨. O 3 ! - 48.33 - 50-60 - FHI -For Sing=0 0 - toring (%) FHI + Foc Sint - - 61.67 A = 33.70 () {Mc=0 (48.33 49) 150 x 6) – (GON 3) FHI *3 = 0 -45.03 - FHI 43 20 FHI Am -15.0) Ub memben in ove sign shows Compression. = put value of fui in eqh @ the FHI + Foc Sin 8 = -61,67 -15.00 + Foc Sin 33.7= -61.67 Fac = -84.09 U (compression) * put value of Foc in equation FHC + Foc Cos o=0 Fuc 84,09 Cos 33.7 20 FHC - of 70 lb (compression. ) ( Tension )

so force in member ☺ DC ; Fpc 84.09 il lb in Compression @ HC; FHC a 2 70 lb in tompressio Tension 3 HIj FHI 15.0) 16 in Compression,

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