Question

a) A 3.0 nC charge is located at (0,0). A second charge of 2.0 nC is located at x = 5.0 m. At a point P on the y-axis determine the electric potential due to the other two charges. You are free to choose the location of this point along the y-axis. b) How much work is required to bring a third charge from infinity to this point P? You are free to choose the value of this third charge. c) Once this third charge is placed at P, determine the magnitude and direction of the total force that this third charge experiences due to the other two charges. Be sure to clearly sketch the charge distribution and all forces.

Answer 1

F let us consider that the third charge is located ou the avis at Sun oll 03 582 y y=5m anal ₂ = 1 ne. 82 0 kol (9.) we have to find electric potential at p due to B and Q2 ".P. =P + P2 tkar ri R 9x10²x3x109 + 9x109x2x10' 5 sfa CScanned with CamScanner 9 P. = 7.95 V

a 3rd as (b) the work done by bringing charge 83 from infinity to the point P will be stored in this charge electric potential energy. .. Electrie potential cuergy of change o k8183 +kQ283 9x10943 +(axlox2x10x1x109. 82 +(8x10 9x3x60-9 -9 XIXIO 5 512 = 7.95×10 9 T © 7.95X60-9 J 14J / of work must be done, ced Tatal Force F = ht2 F = 69,93 quo" x 3.x109 xexo? = 1:08x109 8,2 (512 (tue yaris) fe - Kg83 axlox2x109 x1x109 (552)2 82 = 3.66 1010 N Consument 0.36x10m component of F = F2 caso 0,36 x 10 -9 x 5 552 0:25*109 N (rue xe axis) y-component of = Fg sino = 0.36x109x5 552 = 0.25 X 109 N (tue y axis) CScanned with CamScanner

.:. For = -0.25 xiona a fy = (1.08x109)+(0125 x<0-9) 1:33x109 FR fy N : o resultant force FR = Sfax? + fy? > R=6.95 X10-97 (139x109 )! 1:35x10 Kwaguhtude. Free Fr= -9 N d = tant [ ] = fani G 1+ 33x10-9 0.25.8109 = 1.38 fr $ = 1138 CScanned with CamScanners a direction