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The Keq value depends upon the values of temperature and ∆G. The details of the calculation are given here.
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7) Calculate the key of a reaction at 315 Kand a...
7) Calculate the key of a reaction at 315 °K and a AG° = -35.7 kJ/mol....
7) Calculate the key of a reaction at 315 °K and a AG° = -35.7 kJ/mol. Is the reaction favorable? a. Keq = 8.38*10°; exergonic b. Keq = 8.38*10-5; endergonic c. Keg = 3.76*10°; exergonic d. Keq = 3.76*10-4; endergonic
PLease explain Calculate the Keq of a reaction at 315 °K and a 4Gº = -35.7...
PLease explain
Calculate the Keq of a reaction at 315 °K and a 4Gº = -35.7 kJ/mol. Is the reaction favorable? A. Keq = 3.76*105; exergonic B. Keq = 1.67*10-5; endergonic Oc. Keq = 8.38*105; exergonic D. Keq = 8.38*10-5; endergonic
the next question prevents changes to this answer. Question 24 Calculate the AG* for a reaction...
the next question prevents changes to this answer. Question 24 Calculate the AG* for a reaction at 455K at a Keq = 1,44*104. Is the reaction endergonic or exergonic. OA.-36.2 kJ/mol; endergonic 13.6 kj/mol endergonic OB Ос. 13.6 kJ/mot exergonic OD -36.2 k/mot exergonic Moving to the next question prevents changes to this answer. IMG_3716.jpg IMG_3711:09 o 99 hp 6 7 8 F E Y Т. U
Please help and explain steps, thanks Consider the reaction of silver ion with bromide ion given...
Please help and explain steps, thanks
Consider the reaction of silver ion with bromide ion given below at 25°C. Ag+ (aq) + Br+ (aq) → AgBr (s) What is the value of AGº for this reaction, if the equilibrium constant, Keq = 2.0 x 1012? A) -5.9 kJ/mol B) -70 kJ/mol C) -5.9 x 103 kJ/mol D) -7.0 104 kJ/mol E) -0.69 kJ/mol The rest mass of a proton is 1.00727252 u and that of a neutron is 1.008665 u....
please explain and show calculations Consider the reaction ABB Question 1 1 pts Consider the reaction...
please explain and show calculations
Consider the reaction ABB Question 1 1 pts Consider the reaction above at 27°C with the AGº' = +22,000 J/mol for the forward reaction. The molar concentrations at the beginning of the reaction were [A] = 23 mM and [B] = 4 mm. After 1 hour, the concentrations were [A] = 20 mM and [B] = 10 mM. Gas constant = 8.315 J/mol K Calculate the AG of the reaction after 1 hour. (Round to...
Question 5 For a chemical reaction, AH° 238 = +135.7 kJ and A Sº= +0.379 kJ/K....
Question 5 For a chemical reaction, AH° 238 = +135.7 kJ and A Sº= +0.379 kJ/K. Calculate A Gº 800 A-167.5 kJ B.-132.8 kJ C. +133.9k D-212.8 kJ E.-192.3 kJ ОА OB ОС OD ОЕ Question 6 0.5 pt For a chemical reaction, Hº 238 = +135.7 kJ and A Sº = +0.379 kJ/K. At what temperature will A Gº=0? A. 213K B. 402K C.358 K D. 470K E. 251K ОА OB Ос OD ОЕ Question 7 0.5 For a...
Question 1Coupled Reactions: (a) Calculate Keq for the metabolically unfavourable reaction A → B, for which...
Question 1Coupled Reactions: (a) Calculate Keq for the metabolically unfavourable reaction A → B, for which DGo’=25 kJ mol-1 (b) Using DGo ’ = -32.2 kJ mol-1 for the hydrolysis of ATP, calculate Keq for the coupled reaction A + ATP + H2O → B + ADP + Pi (Hint: consider the two half reactions separately) (c) Assuming the ratio of ATP:[ADP x Pi] is 10-4 , calculate the ratio of A:B in the coupled reaction. (d) How do the...
please show work for these problems, correct answers are circled 18. Consider the following equilibrium: Clip)...
please show work for these problems, correct answers are circled
18. Consider the following equilibrium: Clip) + 2NO) = 2NOCK If 12.0 moles of Cly, 10.24 moles of NO and 2.00 moles NOCI are placed in a 2.00 L container and the system moves to the right to get to equilibrium If there are 100 moles NOCI acquilibrium, calculate the key A 0.006 B5.58 19. What will cause the value of key for an exothermic reaction to decrease? A increasing...
1. A chemical reaction "A" has a DG of -10 kcal/mole. Calculate the key for the...
1. A chemical reaction "A" has a DG of -10 kcal/mole. Calculate the key for the reaction A. Show the equation that you have used and all the calculations to get full credit. (2 pts). 2. State two common features among most of the activate carriers that you have studied in class. (2 points) 3. Study the sequence of the peptide given below and answer the following questions based on the peptide sequence given below. AGLRHTICHMKDCFY (10 points) A. Name...
SOS Question 11 (5 points) What is the equilibrium expression for the following reaction? 2Ag (s)...
SOS
Question 11 (5 points) What is the equilibrium expression for the following reaction? 2Ag (s) + Cl2 (g) = 2AgCl (s) OK = 1/[C12] OK = [Agci12 / [Ag] OK = [Ag]?[c12] OK = [Agci12 / ([Ag]?[Cl2)) OK = (AgCl2 Question 12 (5 points) What is true of the percent inition OK = [AgCl2 Question 12 (5 points) What is true of the percent ionization of a weak acid as the concentration of the weak acid increases? the percent...
7) Calculate the key of a reaction at 315 °K and a AG° = -35.7 kJ/mol. Is the reaction favorable? a. Keq = 8.38*10°; exergonic b. Keq = 8.38*10-5; endergonic c. Keg = 3.76*10°; exergonic d. Keq = 3.76*10-4; endergonic
PLease explain
Calculate the Keq of a reaction at 315 °K and a 4Gº = -35.7 kJ/mol. Is the reaction favorable? A. Keq = 3.76*105; exergonic B. Keq = 1.67*10-5; endergonic Oc. Keq = 8.38*105; exergonic D. Keq = 8.38*10-5; endergonic
the next question prevents changes to this answer. Question 24 Calculate the AG* for a reaction at 455K at a Keq = 1,44*104. Is the reaction endergonic or exergonic. OA.-36.2 kJ/mol; endergonic 13.6 kj/mol endergonic OB Ос. 13.6 kJ/mot exergonic OD -36.2 k/mot exergonic Moving to the next question prevents changes to this answer. IMG_3716.jpg IMG_3711:09 o 99 hp 6 7 8 F E Y Т. U
Please help and explain steps, thanks
Consider the reaction of silver ion with bromide ion given below at 25°C. Ag+ (aq) + Br+ (aq) → AgBr (s) What is the value of AGº for this reaction, if the equilibrium constant, Keq = 2.0 x 1012? A) -5.9 kJ/mol B) -70 kJ/mol C) -5.9 x 103 kJ/mol D) -7.0 104 kJ/mol E) -0.69 kJ/mol The rest mass of a proton is 1.00727252 u and that of a neutron is 1.008665 u....
please explain and show calculations
Consider the reaction ABB Question 1 1 pts Consider the reaction above at 27°C with the AGº' = +22,000 J/mol for the forward reaction. The molar concentrations at the beginning of the reaction were [A] = 23 mM and [B] = 4 mm. After 1 hour, the concentrations were [A] = 20 mM and [B] = 10 mM. Gas constant = 8.315 J/mol K Calculate the AG of the reaction after 1 hour. (Round to...
Question 5 For a chemical reaction, AH° 238 = +135.7 kJ and A Sº= +0.379 kJ/K. Calculate A Gº 800 A-167.5 kJ B.-132.8 kJ C. +133.9k D-212.8 kJ E.-192.3 kJ ОА OB ОС OD ОЕ Question 6 0.5 pt For a chemical reaction, Hº 238 = +135.7 kJ and A Sº = +0.379 kJ/K. At what temperature will A Gº=0? A. 213K B. 402K C.358 K D. 470K E. 251K ОА OB Ос OD ОЕ Question 7 0.5 For a...
please show work for these problems, correct answers are circled
18. Consider the following equilibrium: Clip) + 2NO) = 2NOCK If 12.0 moles of Cly, 10.24 moles of NO and 2.00 moles NOCI are placed in a 2.00 L container and the system moves to the right to get to equilibrium If there are 100 moles NOCI acquilibrium, calculate the key A 0.006 B5.58 19. What will cause the value of key for an exothermic reaction to decrease? A increasing...
1. A chemical reaction "A" has a DG of -10 kcal/mole. Calculate the key for the reaction A. Show the equation that you have used and all the calculations to get full credit. (2 pts). 2. State two common features among most of the activate carriers that you have studied in class. (2 points) 3. Study the sequence of the peptide given below and answer the following questions based on the peptide sequence given below. AGLRHTICHMKDCFY (10 points) A. Name...
SOS
Question 11 (5 points) What is the equilibrium expression for the following reaction? 2Ag (s) + Cl2 (g) = 2AgCl (s) OK = 1/[C12] OK = [Agci12 / [Ag] OK = [Ag]?[c12] OK = [Agci12 / ([Ag]?[Cl2)) OK = (AgCl2 Question 12 (5 points) What is true of the percent inition OK = [AgCl2 Question 12 (5 points) What is true of the percent ionization of a weak acid as the concentration of the weak acid increases? the percent...
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