A 102.08 kg skater moving initially to the right at 5.3 m/s on rough horizontal ice...

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A 102.08 kg skater moving initially to the right at 5.3 m/s on rough horizontal ice...

A 102.08 kg skater moving initially to the right at 5.3 m/s on rough horizontal ice comes to rest uniformly (constant acceleration) in 5.1 s due to friction from the ice. What is the acceleration of the skater due to friction?

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Answer 1

Answer #1

from Newtons First equation V=ut at bial- velocidy = 5.3mls final veloci cidy 0 t Sil sec. so o = 5-3 + ax 5.1 o -5.3 5.1 as if any inquires please comment and if you satisfied please like.

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Answer 2

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A 102.08 kg skater moving initially to the right at 5.3 m/s on rough horizontal ice...

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A 102.08 kg skater moving initially to the right at 5.3 m/s on rough horizontal ice...

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