dP [20pt] 7. Suppose that the certain population obeys the logistics equation = 0.025 - P....
I really need to for help please everyone i begging u all. Suppose that the certain population obeys the logistics equation dP dt 0.025. P.(1 where C is the carrying capacity. If the initial population P = C/3, find the time at which the initial population has doubled, i.e., find time l" such that P(1") = 2P=2C/3.
2. Suppose a population P(t) satisfies the logistic differential equation dP dt = 0.1P 1 − P 2000 P(0) = 100 Find the following: a) P(20) b) When will the population reach 1200? 2. Suppose a population P(t) satisfies the logistic differential equation 2P = 0.1P (1–2000) = 0.1P | P(0) = 100 2000 Find the following: a) P(20) b) When will the population reach 1200?
A population P obeys the logistic model. It satisfies the equation dp 2 dt = 500 P(5 – P) for P >0. (a) The population is increasing when - Preview <P < 5 Preview (b) The population is decreasing when P > 5 Preview (c) Assume that P(0) = 4. Find P(40). P(40) = 1.93 * Preview
Suppose that the rate of change of a population is given by: dP dt = kP(M-P) a) What model of population growth is this ? b) What does it predict for the growth of the population as the population increases ? c) Sketch what happens to the population if the initial population, Po, were such that G) 0< Po< M/2, (ii) M/2 < PoM and (iii) Po > M (all on the same graph of population as a function of...
3 pts) Suppose that a population develops according to the logistic equation dP dt = 0.15P - 0.0006P2 where t is measured in weeks. a) What is the carriying capacity? b) Is the solution increasing or decreasing when P is between() and the carriying capacity? C) Is the solution increasing or decreasing when P is greater than the carriying capacity? Note: You can earn partial credit on this problem.
Suppose that a population of hacteria grows according to the logistic differential equation dP =0.01P-0.0002P2 dt where Pis the population measured in thousands and t is time measured in days. Logistic growth differential equations are often quite difficult to solve. Instead, you will analyze its direction field to acquire infom ation about the solutions to this differential equation. a) Calculate the maximum population M that the sumounding environment can austain. (Note this is also calked the "canying capacity"). Hint: Rewrite...
Problem #6: A model for a certain population P(1) is given by the initial value problem dP-H10-3-10-13 P), dt P(0)= 100000000, where t is measured in months (a) What is the limiting value of the population'? (b) At what time (i.e., after how many months) will the populaton be equal to one half of the limiting value in (a)? Do not round any numbers for this part. You work should be all symbolic.) Problem #6(a): 10000000000 Enter your answer symbolically,...
(1 point) Biologists stocked a lake with 500 fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be 5500. The number of fish doubled in the first year. (a) Assuming that the size of the fish population satisfies the logistic equation dP dt - 2P (1-1) determine the constant k, and then solve the equation to find an expression for the size of the population after t years. k= 0.7985...
POPULATION MODELS: PLEASE ANSWSER ASAP: ALL 3 AND WILL RATE U ASAP. The logistic growth model describes population growth when resources are constrained. It is an extension to the exponential growth model that includes an additional term introducing the carrying capacity of the habitat. The differential equation for this model is: dP/dt=kP(t)(1-P(t)/M) Where P(t) is the population (or population density) at time t, k > 0 is a growth constant, and M is the carrying capacity of the habitat. This...
0.08t The size P of a certain insect population at time t (in days) obeys the function P(t)- 600 e (a) Determine the number of insects at t-0 days. (b) What is the growth rate of the insect population? (c) What is the population after 10 days? (d) When will the insect population reach 960? (e) When will the insect population double?