Question

DESCRIPTION:

You will be given a 1-D array, called wordFun, of Strings. The array has an unknown number of cells filled with data. As before, the array will already be filled with strings, some of which contain the string "Angela".

You will create a method called countItUp which returns and integer array containing the number of times each of the letters in my name occur within the strings within this array.

For example, if the input array was

wordFun = {"A", "Angela", "B", "gill", "e", "e"}

Counts would be:

A: 2
n: 1
g: 2
e: 3
l: 3
a: 1

thus the method countItUp would return the integer array {2, 1, 2, 3 ,3, 1}.

INPUT:

All input has been handled for you:

• A filled 1-D string array called wordFun
  

METHOD PROCESSING:

Use loops, arrays, and print statements to complete a new method called countItUp . This method should do the following:

• Read the wordFun array without altering its data
• Iterate through the wordFun array using a for loop
  • For each string in the array, loop through the letters and determine if any are one of those in my name ('A', 'n', 'g', 'e', 'l', or 'a')
    • Keep a count of the number of occurrences of each of those letters, incrementing every time you see another one.

METHOD RETURN VALUE:

• Once the the counts have been completed, the method would return those counts as an integer array of the form:
  
  { COUNT_OF_A, COUNT_OF_n, COUNT_OF_g, COUNT_OF_e, COUNT_OF_l, COUNT_OF_a}

NOTE: Only complete the countItUp method. Do not alter any other code.

Sample input/output:

Method argument	Method Return Value
{"A", "Angela", "B", "gill", "e", "e"}	{ 2, 1, 2, 3, 3, 1}
{"Angela", "Bill", "apple", "pear"}	{ 1, 1, 1, 3, 4, 3}

Given code:

import java.util.Scanner;

/**
* @author Angela Siegel
* @date 07/17/2020
*/

public class Question3 {

/**
* countItUp method
*/

   /*=====================================
   || DO NOT ALTER CODE BELOW THIS LINE ||
   =====================================*/

public static void main(String[] args) {
Scanner in = new Scanner(System.in);
String[] words = in.nextLine().split(" ");

char[] letters = {'A','n','g','e','l','a'};
int[] counts = countItUp(words);
  
for (int i=0; i<6; i++) {
System.out.println(letters[i] + ": " + counts[i]);
}
}
}

Answer 1

CODE:

import java.util.Scanner;

/**
* @author Angela Siegel
* @date 07/17/2020
*/

public class Main {
  
   /**
   * countItUp method
   */
  
   public static int[] countItUp(String[] words) {
       int counts[] = new int[6]; // Initially assigned to '0'
       for (String word : words) { //Looping through all give words
           for (int i = 0; i < word.length(); i++) { //Looping through each word
               if(word.charAt(i) == 'A') //If character is 'A' then increment 0th index count
                   counts[0]++;
               else if(word.charAt(i) == 'n') //If character is 'n' then increment 1th index count
                   counts[1]++;
               else if(word.charAt(i) == 'g') //If character is 'g' then increment 2th index count
                   counts[2]++;
               else if(word.charAt(i) == 'e') //If character is 'e' then increment 3rd index count
                   counts[3]++;
               else if(word.charAt(i) == 'l') //If character is 'l' then increment 4th index count
                   counts[4]++;
               else if(word.charAt(i) == 'a') //If character is 'a' then increment 5th index count
                   counts[5]++;
           }
       }
       return counts; //returning counts array
   }

   /*
   * =====================================
   || DO NOT ALTER CODE BELOW THIS LINE ||
   * =====================================
   */

   public static void main(String[] args) {
       Scanner in = new Scanner(System.in);
       String[] words = in.nextLine().split(" ");

       char[] letters = { 'A', 'n', 'g', 'e', 'l', 'a' };
       int[] counts = countItUp(words);

       for (int i = 0; i < 6; i++) {
           System.out.println(letters[i] + ": " + counts[i]);
       }
   }
}

CODE SCREENSHOT:

1 import java.util.Scanner; 2 3/** 4 * @author Angela Siegel 5* @date 07/17/2020 6 */ 7 8 public class Main { 9 10 /** 11 * countItUp method 12 */ 13 14 public static int[] countItUp(String[] words) { 15 int counts[] = new int[6); // Initially assigned to '0' 16 for (String word : words) { //Looping through all give words 17 for (int i = 0; i < word.length(); i++) { // Looping through each word 18 if(word.charAt(i) == 'A') //If character is 'A' then increment Oth index count 19 counts[0]++; 20 else if(word.charAt(i) == 'n') //If character is 'n' then increment 1th index count 21 counts[1]++; 22 else if(word.charAt(i) == 'g')//If character is 'g' then increment 2th index count 23 counts[2]++; 24 else if(word.charAt(i) == 'e') //If character is 'e' then increment 3rd index count 25 counts[3]++; 26 else if(word.charAt(i) == '1') //If character is 'I then increment 4th index count 27 counts[4]++; 28 else if word.charAt(i) == 'a') //If character is 'a' then increment 5th index count 29 counts[5]++; 30 31 32 return counts; //returning counts array 33 ) 34 35 36 37 II DO NOT ALTER CODE BELOW THIS LINE 11 38 39 */ 40 } **

public static void main(String[] args) { Scanner in = new Scanner(System.in); String[] words = in.nextLine().split(" "); char[] letters = { 'A', 'n', 's', 'e', 'T, 'a' }; int[] counts = countItUp(words); 41 42 43 44 45 46 47 48 49 50 51 52) 53 for (int i = 0; i < 6; i++) { System.out.println(letters[i] + ' + counts[i]); سب }

OUTPUT SCREENSHOT:

+ C Output Input optional A Angela B gill e e Accepted 0.1295, 12296KB n A: 2 n: 1 g: 2 e: 3 1: 3 a: 1

Hope this will help you. Let me know, still if you have any queries..

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