Question

16:10 29-7 Math 102 Summer 2019-202... pelo docenion beton 00:49:28 Progress: 7% 3 of 14 + The Partial fraction form of x²–2x+5 А Rx)= (x - 1)(x2+1) X-1 C= BX+C x²+1 the value of -1 -4 -2 -3 Previous Next Finish

Answer 1

SOLUTION f(x) = x?- 2x + 5 A + Bx & C (32-1)(x+1) X-1 70 71 c A (beri) ve+i) + (Bx +C)(x-1) (2-1)(2+) a A x² + A + B x² Bret carc (2-1) G+) (A + B) x - CB-C) x + (A - (x-1)(x+1) Now, on comparing coefficients of numerator RMS, in LHS and we have A + B = 1 B-c=2 2 A - ( = 5 3 2 + (A - () - (B-1) = 5 - 2 AC-Btc 3 A - B 3 ot + ☺ 7 (A+B) + (A - B) = 1+ 3 it 2A 4 A : 2 Put A in B = 7 17 put ß in 7 C = -3