Question

c/c++

Passing arrays as arguments to functions. The main() is given, write the function 'average' (Study the syntax of passing an array as a function parameter) The program prompts the user to first enter the number of tests given in a course, and then prompts him/her to enter the mark for each test. The marks are stored in an array. This takes place in the main() function. It then passes the array to a function named 'average' that calculates and return (to main) the average mark of all tests. main() will then print the average mark. 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 The name, ID and section number that appear at the beginning of the output of the program should be your own, not the ones used in the sample Note: results printed must show the data entered at run time, not the data shown in the sample run below! Sample run: My name: Smith, Peter My ID: 300999999 My section: 61 Enter number of tests : 4 Enter mark for test 1 : 6.5 Enter mark for test 1 : 14.5 Enter mark for test 1 : 12 Enter mark for test 1 : 17 35 36 37 38 39 The average mark is 12.50

Answer 1

`Hey,

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#include <stdio.h>
double average(int n,double a[])
{
int i;
double s=0;
for(i=0;i<n;i++)
s=s+a[i];
return s/(double)n;
}
int main()
{
int n;
double a[10];
printf("\nEnter number of tests : ");
scanf("%i",&n);
int i;
printf("\n");
for(i=0;i<n;i++)
{
printf("Enter mark for test %i : ",i+1);
scanf("%lf",&a[i]);
}
printf("\nThe average mark is %.2f\n",average(n,a));
return 0;
}

main.c 1 #include <stdio.h> 2 double average(int n, double a[]) 3-{ 4 int i; 5 double s=0; 6 for(i=0;i<n;i++) 7 s sta[i]; 8 return s (double)n; 12 10 int main() 11- { int n; 13 double a[10]; 14 print("\nEnter number of tests : "); 15 scan ("%i",&n); 16 int i; 17 print("\n"); K input Enter number of tests : 4 Enter mark for test 1 : 6.5 Enter mark for test 2 : 14.5 Enter mark for test 3 : 12 Enter mark for test 4 : 17 The average mark is 12.50

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