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Friction losses in expansion, contraction, and pipe fittings Example An elevated storage tank contains water at 15°C as shown
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Zq=H H de = 3 in=0.0762m Solution 4 1 K=0.75 -50m Uz 1om dz=8 in = 0.2032m ų K=1 K=0.75 * 25m K=0;75 4 Zzzom 3m Linch=0-02549& chart # Rez = Shade u 11*10-3 (1-754245) 744 4*0.0184 752 +3*0.75/ Relative = € = 0.045* Horizon = 2-215*10-4 0.80323 # At# = 11.7224m Abbron ų = 0 PL = P = 1 atm Applying Bernoullies eqfuation between f@. TO fo +2 + zg the + 72 the H = (0-2467)2

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