Question

10. As the cell given below operates, the strip of silver gains mass (only silver) and the concentration of silver ions in th

0 1
Add a comment Improve this question Transcribed image text
Answer #1

Pb/P60ml | Apares lag Anode acts as electrode. Oxidation Negative takes place at anade. at anade ++ Pb P++ tae (s) caq at Cat

Add a comment
Know the answer?
Add Answer to:
10. As the cell given below operates, the strip of silver gains mass (only silver) and...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • In a galvanic cell, one half-cell consists of a lead strip dipped into a 1.00 M...

    In a galvanic cell, one half-cell consists of a lead strip dipped into a 1.00 M solution of Pb(NO3)2. In the second half-cell, solid uranium is in contact with a 1.00 M solution of U(NO3)3. Pb is observed to plate out as the galvanic cell operates, and the initial cell voltage is measured to be 1.672 V at 25°C. (a) Write balanced equations for the half-reactions at the anode and the cathode. Show electrons as e-. Use the smallest integer...

  • One half-cell in a voltaic cell is constructed from a silver wire electrode in a AgNO3...

    One half-cell in a voltaic cell is constructed from a silver wire electrode in a AgNO3 solution of unknown concentration. The other half-cell consists of a zinc electrode in a 1.9 M solution of Zn(NO3)2. A potential of 1.48 V is measured for this cell. Use this information to calculate the concentration of Ag (aq). E® Zn/Zn2+ = -0.763 V Eº Ag/Ag+ = 0.7994 V Concentration = Submit Answer Try Another Version 6 item attempts remaining

  • 20. Which one of the following reactions is spontaneous (in the direction given) under standard e...

    Please answer the following questions! 20. Which one of the following reactions is spontaneous (in the direction given) under standard electrochemical conditions? +2Br- Mg+ Br2 What is the cell potential for a cell constructed by immersing a strip of manganese in a 1. M MnSO4 solution and a strip of iron in a 1.0 M FesO4 solution and completing the circuit by a wire and a salt bridge? 21. b. +1.62 V c. -0.74 V d. +0.74 V e. +1.21...

  • 19 20 Question 16 Half-cell Potentials: Half Reaction: E' value + 0.80 V +0.77 V Agte...

    19 20 Question 16 Half-cell Potentials: Half Reaction: E' value + 0.80 V +0.77 V Agte → AS Fe3+ + + Fe2+ Cu2+ 2e → Cu Pb2+ + 2e → Pb +0.34 V -0.13 V Ni2+ + 2e → NI -0.25 V - 0.40 V Cd2+ +2e → ca Fe2+ + 2e → Fe Zn2+ + 2e → Zn -0.44 V - 0.76 V A13+ +3 → AI - 1.66 V Consider an electrochemical cell constructed from the following half...

  • Pb^2+ +2e- __> Pb e=-0.13V Ag+ +1e-__> Ag e=+0.80V Pb(s)| Pb2+ (1M) || Ag+ (1M) |...

    Pb^2+ +2e- __> Pb e=-0.13V Ag+ +1e-__> Ag e=+0.80V Pb(s)| Pb2+ (1M) || Ag+ (1M) | Ag(s) Determine which of the following statements about the cell shown are True or False. The silver half-cell is the cathode. True False  The mass of the silver electrode is decreasing. True False  Anions move to the silver half-cell. True False  Electrons are spontaneously produced in the lead half-cell. True False  The cell, as represented by the line notation, is a voltaic cell. True False  The standard cell potential,...

  • please and please choose the right answer and please make it clear for my understanding 1-Which...

    please and please choose the right answer and please make it clear for my understanding 1-Which of the following statements are false? Oxidation and reduction half-reactions occur at electrodes in electrochemical cells All electrochemical reactions involve the transfer of electrons Oxidation occurs at the anode All voltaic (galvanic) cells involve the use of electricity to initiate nonspontaneous chemical reactions Reduction occurs at the cathode 2-During the electrolysis of aqueous KCl solution using inert electrodes, gaseous hydrogen is evolved at one...

  • Muyuulin (1JJ. Part III: Determination of a Solubility Product In Part Ill you will prepare a...

    Muyuulin (1JJ. Part III: Determination of a Solubility Product In Part Ill you will prepare a saturated solution of silver carbonate (Ag2CO3) and deten solubility product constant of Ag2CO3. Ag2CO3(s) = 2 Agt(aq) + CO32-(aq) (17) In making the solution, 1.0 mL of 0.10 mol/L AgNO3 will be added to specified volume mol/L Na2CO3. The limiting reagent in this reaction will be the silver ions. Use of an excess an of anion allows for a relatively simple calculation of the...

  • For a voltaic (or galvanic) cell using Ag, Ag+ (1.0M) and Zn Zn2+ (1.0 M) half-cells, which of the following statements is incorrect

    For a voltaic (or galvanic) cell using Ag, Ag+ (1.0M) and Zn Zn2+ (1.0 M) half-cells, which of the following statements is incorrect? (a) The zinc electrode is the anode. (b) Electrons will flow through the external circuit from the zinc electrode to the silver electrode. (c) The mass of the zinc electrode will decrease as the cell operates. (d) The concentration of Ag will decrease as the cell operates. (e) Reduction occurs at the zinc electrode as the cell operates.

  • Be sure to answer all parts. A galvanic cell consists of a silver electrode in contact...

    Be sure to answer all parts. A galvanic cell consists of a silver electrode in contact with 305 mL of 0.100 M AgNO3 solution and a magnesium electrode in contact with 265 mL of 0.700 M Mg(NO3)2 solution. (a) Calculate E for the cell at 25°C. V (b) A current is drawn from the cell until 2.20 g of silver have been deposited at the silver electrode. Calculate E for the cell at this stage of operation. V

  • Consider an electrochemical cell constructed from the following half cells, linked by a KCl salt bridge....

    Consider an electrochemical cell constructed from the following half cells, linked by a KCl salt bridge. a Fe electrode in 1.0 M FeCl2 solution a Sn electrode in 1.0 M Sn(NO3)2 solution Fe2+ + 2e- → Fe                                  Eo = -0.44 V Sn2+ + 2e- → Sn                                  Eo = -0.14 V When the cell is running spontaneously, which choice includes only true statements and no false ones? Select one: a. The iron electrode gains mass and the iron electrode is the...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT