Question

Question 5 of 27 (1 point) Attempt 1 of 1 | View question in a ropur 1h 10m Remaining 8 3 Section Working at home: According to the U.S Census Bureau, 35% of men who worked at home were college graduates. In a sampl of 473 women who worked at home, 164 were college graduates.

Answer 1

Given n = 473 and X = 164

We need to construct the 95% confidence interval for the population proportion. We have been provided with the following information about the number of favorable cases: Favorable Cases X = 164 Sample Size N = 473 473 and the number The sample proportion is computed as follows, based on the sample size N of favorable cases X = 164: p X N 164 473 -0.347 The critical value for a = 0.05 is ze = 21-a/2 = 1.96. The corresponding confidence interval is computed as shown below: p(1-P) p(1-P) CI(Proportion) - Zc , + V n n 0.347 – 1.96 x 0.347(1 -0.347) 473 0.347 + 1.96 x 0.347(1 – 0.347) 473 (0.304, 0.39) Therefore, based on the data provided the 95% confidence interval for the population proportion is 0.304 <p<0.39, which indicates that we are 95% confident that the true population proportion pis contained by the interval (0.304, 0.39)

Answer: A 95% confidence interval for the proportion of women who work at home is 0.304 < p < 0.390