Question

need help on all parts ASAP please and thank you

Required information A 1.25-in. steel plate and a 0.5-in. gray cast iron plate are compressed with one bolt and nut. The bolt is in-13 UNC. AV N American Standard plain washer is used under the head of the bolt and under the nut. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Determine a suitable length for the bolt, rounded up to the nearest Vin. The length of the bolt is in.

Answer 1

En between nut height Thickness of steel plate= 1.25 in Thickness gray cast cast inon plade 0.5 in compressed with one bolt and nut. The bolt is 1/2 in-13 UNC. The washer used is of A N American standard. from table A-32, the washer thickness is 0.095 in arus, l= 1.25 +0.5+210.095) = 1.94 in. for the bolt, from table A-31, A = 7/16 in . Lal+H = 81.94 + 7/16= 2.3775 in Rounding up, L= 2.5 in is 2.5 in. So length of bolt Here La- ad + 1/4 = 2x0.5 +0.25= 1.25 in b = L-LF 2.5-1.25= 1.25 in, le = l-la = 1.94-1.25=0.69 in A = 5 (0.59%40. 1963 in? from table 8-2, A2= 0.1419 in? from formula, E = 30mpsi (Table 8-8) Ad At E 0.1963*0.1419x30 Adlt +Arld (o 196 3x0.69)+ (0.1419 x 1:25) Kb 2.67 Mebflin. Any

0.75 in I 0.095 in 10.875 ini OSCO " To.095 in D=0.75 in, Each sted washen faustrumi t = 0.095 in, d= 0.531 in 30mpsi, from ean 0.5774 x 30 x 0.531 1.155(0.095)+ 0.15-0.531160 75+0:37] 89.20 Mebflin 1.155(0-09540-75+0.53136.75-0-531 Pop plate steel frustrum, t= 0.875 in, d-0.5 in D= 0.75 +260.095) tan30 = 0.860 in , & = 30mPsi from equation, above K2= 34.82 Mabillin Top plate, lower sted frustrium, t= 0.375 in, d = o.sin D= 0.860 + (2x 60 dan 30) - 1.4828 in, E= 30mpsi from eanuation as above, K3= 152.9 Mestlin for lower cast iron, t= as in, dr0.5 in DE 0.75 +6x0.095x+an 30)=0.860 in, E = 14.5in from equation, as above, Iku = 21.79 Mestlin so km= (2/4, + / kg + uy trku) 89.6674 Mist/in Am So material stiffness is 9.6674 Mestlin.
1) length of bolt is 2.5 in

2) stiffness of bolt is 2.67Mlbf/in

3)material stiffness is 9.6674 Mlbf/in

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