Evaluate the integral by using partial fractions. Please write in clear steps. 2) Evaluate the integral...
(Calc 2) 1) Evaluate the given integral using by partis method: S 2xe*dx 2) Evaluate using partial fractions method: S •dx x²-x-6 5x
Express the integrand as a sum of partial fractions and evaluate the integral. 48x2 s dx (x-24)(x+8)2 Express the integrand as a sum of partial fractions. S 48x? dx= (x - 24)(x+8)2 SO dx Evaluate the indefinite integral. 48x? (x - 24)(x + 8)2 dx =
6. Use the method of partial fractions to evaluate the indefinite integral. 8x' + 13x •dx (x + 2) 7. Consider a. Using complete sentences, explain why the integral is improper. b. Evaluate the improper integral to determine its convergence or divergence.
3) Complete the Partial Fractions and find the indefinite integral r-3x5 +4x4 +2x3 10x2 +4x +8 x3(x 1)2(x +2)2 dx 3) Complete the Partial Fractions and find the indefinite integral r-3x5 +4x4 +2x3 10x2 +4x +8 x3(x 1)2(x +2)2 dx
Evaluate using partial fractions 4 + 9x2 +r+2 dx 2 +9
Please show all workings and steps for question 1: 1. Evaluate the indefinite integral. 3 - a) [(5x2 – 2x) +6x*) dx х b) \ x2 -dx 4x3 + 1 dx 1 + (ex)2
Evaluate the following integral using the partial fractions technique. Give you answer in exact form, in terms of In(x-7), In(x2+1) and arctan(x), ignoring the integration constant. For help on integration methods click here. 3+3 dc
(1 point) Calculate the integral below by partial fractions and by using the indicated substitution. Be sure that you can show how the results you obtain are the same. 1. 2x - dx 1 x² – 64 +C. First, rewrite this with partial fractions: I ZX64 dx = | dx + dx = (Note that you should not include the +C in your entered answer, as it has been provided at the end of the expression.) Next, use the substitution...
14) Express the integrand as a sum of partial fractions and evaluate the integral
please show all work and steps thank you :) Evaluate the integral. 1 $5x(x2 - 1) '?dx 0 1 5x(x2 - 1)?dx = (Type an integer or a simplified fraction.) 0