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Consider 5 processes whose Arrival time and CPU Burst time is as follows (Process no: Arrival time: Burst time): P1:0,6 P2:2,

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Answer #1

SJF ( Non-Preemtive) approach starts with selecting the process having minimum
burst time and complete the entire execution of process without interuppted by any other
process.

The order of execution and their waiting time and Turnaround time is shown in the
below table.

Average waiting Time = 5.40
Average Turnaround Time = 10.60

Answer: 5.40,10.60 (Option 2)

Process 1 Arrival time Bent time waiting time Turn around time Pi G 6 por 2 4 6 10 P3 3. 2 3 PA vi 5 7 iz Ps 6 9 11 20 27 53

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Answer #1

SJF ( Non-Preemtive) approach starts with selecting the process having minimum
burst time and complete the entire execution of process without interuppted by any other
process.

The order of execution and their waiting time and Turnaround time is shown in the
below table.

Average waiting Time = 5.40
Average Turnaround Time = 10.60

Answer: 5.40,10.60 (Option 2)

Process 1 Arrival time Bent time waiting time Turn around time Pi G 6 por 2 4 6 10 P3 3. 2 3 PA vi 5 7 iz Ps 6 9 11 20 27 53

0 0
Add a comment
Answer #1

SJF ( Non-Preemtive) approach starts with selecting the process having minimum
burst time and complete the entire execution of process without interuppted by any other
process.

The order of execution and their waiting time and Turnaround time is shown in the
below table.

Average waiting Time = 5.40
Average Turnaround Time = 10.60

Answer: 5.40,10.60 (Option 2)

Process 1 Arrival time Bent time waiting time Turn around time Pi G 6 por 2 4 6 10 P3 3. 2 3 PA vi 5 7 iz Ps 6 9 11 20 27 53

0 0
Add a comment
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