Question

7.3.49 Question Help Given a population in which the probability of success is p=0.35, if a sample of 300 items is taken, then complete parts a and b. a. Calculate the probability the proportion of successes in the sample will be between 0.32 and 0.37. b. Calculate the probability the proportion of successes in the sample will be between 0.32 and 0.37 if the sample size is 100 a. The probability the proportion of successes in the sample will be between 0.32 and 0.37 is . (Round to four decimal places as needed.)

Answer 1

O Answert (7.3.49 Given, Hees Pin au normal paramety Scaun p=0.ar n=300. npu-p) >10. Now sampling Astributions for p. n mean fue sampling dertoo Sutron lepa pe 0.15 Standard dersation for sampling 182/P(1-P) PL-P) 10.36120.35) M Istrisution des n 100 0.02753785212 0.0275 Nog the the sample prosability the pagsaction of rullenes de well se between 0.32 and 0.37 de

p-up 0.32-0.35 PCO. 120 p <0.371 - PU88.0.171 - P (P < 0.12) @ P (P-upo Haceton PC2 <0.729.42.733-p122-1.090109) ~P(200.73)-P(22-1. 09) 0.37 0.15 0.0278 0.0275 From the standard normal dest rosetion table & O. 767.30-0. 11786 = 0. 62944 20. 6294 Foy decond place n100 .: P ( 0 3 2 2 3 < 0: 37) = 0.6Lq4 (3) For sample pice of 100 Mg-p= 0.35 Remains rame) 0.31-0.15) 0.047696960 LDO 0.0477 los p=0.0477

? Nog. The peosaldadly that proportion of succem, in the reample will se schween Ooll and on atos P(0.32 CP CO.7) = P (8 (0:27) - P18 (0.32) =P(Palla Los 4+ 0,25 J-pl P-MP ор 0,0477 PC2C 0.4192612117-PVC -0.6289101176) ~ P12.20.42) - P(22-0.63) Oo JL-0035 2 . 0477 From the Wandard nound table 0.66276--0.26435 O. 1954). O, 1984 any decimal placu IP (0.12 C P < 0.37 ) = 0. 1984