Question

For the following specifications of lines find the equation of the line in (a) General form (b) Point-gradient form (c) Gradient intercept form i. Passing through (2,2) with gradient 3 ii. Passing through (-3,7) parallel to the line 38-4y+1=0 Passing through (1.1) perpendicular to the line 7x+3y-5=0

Answer 1

For the following Specifications.co lines find the equation of the line (as General form Ob point. gradient form c) Gradient intercept form Ú) Passing through (22)with gradient 3 General form y-y = m ( x-x1) y-2=3(2-2) - 2 = 3X-6 37-7+2-6 = 0 3 x - y - 4 = 0 (5) Point -gradient form y - y = m(x-26) 19-2=3(2-2) (9) y-2 23(2-2) Y-2 -3X-6 3x-1-4=0 34-4-4 3x-y 4 33 } -1 X-Gradient 4 √ y-Gradiant is -4

Line 3 mese peallel to the Passing line parallel to te tine is SX-4 Y +K=0 pasting through point (-3,7) 3(-3)-407)+=0 -9-2$+0 is = 31 reare line in General form 3x-4ž +37=0 Point gradiant form 10 = mxtc 3 at 37 2 x + 37 y = 3 x + 37 lb AY a دعا Gradiant intercept from 3x-41 = -37 3x-49 -37 3 + 4y = 37 + 2) 31 3 x-Gradiant is - 37 mogen og Listen 4 I-Gradict 37 7 4

(11) passing throughs (w) perpendicular line 73.+3y-550 Solution Given to the ecuation m Gradient m- y-Y, 71737-520 34 - ~7x+5 y = - 7 / at 5 - 7 The negchre reuprocal of 3 mcn-n, y-1-3 (2-1) ly-17= Zine 74-7 = 3 n-3 34-74-3+7= 0. 3 x-74 +4=0 General torm is 3a-74 + 4 =0 Point Gradient form 71= 32+ 4 y = 3 x + 4 y = match I'm 3 I

, Goadiant intercept foom azhthure t--RL-RE 따R - | 고 의 t것디 4 긴 t = 오 그 기어 Gradiant - 4 y-Gradiant y T 3