Question

Help!

a Calculate the wavelength of light that produces its first minimum at an angle of 36.99 when falling on a single slit of width 1.00 um. b. An aircraft maintenance technician walks past a tall hangar door that acts like a single slit for sound entering the hangar. Outside the door on a line perpendicular to the opening in the door a jet engine makes a 600-Hz sound. At what angle with the door will the technician observe the first minimum in sound intensity if the vertical opening is 0 800 m wide and the speed of sound is 340 m/s?

Answer 1

The angle a Solution:- diffraction o, for the first minimum is given by a sino, - (0) Given, - 100m 1.00um 56.9° . Substituta the values in eas: (i) we get, job Sin (36.9°) a 600.42 x 10 9 - 1600 42 nm. . m i. Wavelength of Light produces 600, 42 nm. b As the door serves Some known which a sound as a single slit with then angle at width w, with a known wavelength be given by would would 2, diffracts the following equation: - w sino ma (1 Now, À : V f 340 600 0.567 m. the angle Thus, Knowing what the wavelength is, then we can find at which the 1st minima of this equn (1) Sint sound would occurs, using we get ma

of the door is 0.800 m, Knowing the width we get, 1 X 0,567 o Sint 1 L Sint 0.70881 @ 45.1° would be observed Thus, the 1st at an angle minima of 45.1° with the door.